j162 24 2 j40 요일 100 V/30 ( -jl N j4 2 =-Q 8 j102 3 j9 2 -j10 2= 10 Ω 32 82 QUESTION 3 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the voltage across the -18 ohm capacitor. O 14V RMS O 8.5V RMS O 34V RMS O 23V RMS QUESTION 4 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the current through the j9 ohm inductor. O 2 8A RMS O 11.1A RMS O 850mA RMS O 6.3A RMS e

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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1
j16 2
j40 2
24 2
j40 2
100 V/30° (
+-jl N
j4 2 =-80
j10 2
-j10 2=
j9 2
10 2
3Ω
82
QUESTION 3
Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the voltage across the 8 ohm capacitor.
O 14V RMS
O 8.5V RMS
O 34V RMS
O 23V RMS
QUESTION 4
Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the current through the j9 ohm inductor.
O 2.8A RMS
O 11.1A RMS
O 850mA RMS
O 6.3A RMS
ll
Transcribed Image Text:j16 2 j40 2 24 2 j40 2 100 V/30° ( +-jl N j4 2 =-80 j10 2 -j10 2= j9 2 10 2 3Ω 82 QUESTION 3 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the voltage across the 8 ohm capacitor. O 14V RMS O 8.5V RMS O 34V RMS O 23V RMS QUESTION 4 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the current through the j9 ohm inductor. O 2.8A RMS O 11.1A RMS O 850mA RMS O 6.3A RMS ll
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