17) In the two circuits shown here, the probabilities for successful operation forthe sub-elements are given as:PA = 0.9PD = 0.93PG = 0.96 | P₁ = 0.99PB = 0.91PE == 0.94PH = 0.97Pc = 0.92PF = 0.95P₁ = 0.98Determine the probability of failure for each of the circuits.Note: All systems operated independently.ADCBE00AB00C DEFG

Answered: 7) In the two circuits shown here, the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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1
7) In the two circuits shown here, the probabilities for successful operation for
the sub-elements are given as:
PA = 0.9
PD = 0.93
PG = 0.96 | P₁ = 0.99
PB = 0.91
PE =
= 0.94
PH = 0.97
Pc = 0.92
PF = 0.95
P₁ = 0.98
Determine the probability of failure for each of the circuits.
Note: All systems operated independently.
A
D
C
B
E
00
A
B
00
C D
E
F
G

Expert Solution

Step 1: Summary of the question

According to the question, for the given circuit as shown below

the probability of successful operation of the sub-elements are,

$straight P subscript straight A space equals space 0.9 comma straight P subscript straight B space equals space 0.91 comma straight P subscript straight C space equals space 0.92 comma straight P subscript straight D space equals space 0.93 comma straight P subscript straight E space equals space 0.94 comma straight P subscript straight F space equals space 0.95 comma straight P subscript straight G space equals space 0.96 comma straight P subscript straight H space equals 0.97 comma straight P subscript straight I space equals space 0.98 comma straight P subscript straight J space equals space 0.99 comma$

We need to calculate probability of failure of each circuit.

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