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J VDD RD - Vout You may have already noticed that the common source amplifier circuit is basically the same as the NMOS RTL inverter, just used for different purposes. The slope of the inverter VTC (Vout-Vin curve) is also the small- signal voltage gain of the common source amplifier. Assume VDD = 5V and Vin M₁ Vthn 0.7 V for the NMOS, use PSPICE to simulate the VTC (sweep from 0 to 5 V) of the common source amplifier for the following conditions: (a) Fix RD = 100 kN, L = 1 µm, W = 1 μm. Vary kn² = 20, 100, and 500 μА/V². (b) Fix kn' = 100 µA/V², R₁ = 100 kQ, L = 1 μm. Vary W = 1, 5, and 50 μm. (c) Fix kn' = 1 100 μA/V², L = 1 µm, W= 1 µm. Vary RD = 10 k2, 100 kQ, 1 MQ. Compare the slopes of the VTCs (which correspond to the voltage gains of the amplifiers) you obtained from the various conditions in a-c and explain your results.

J VDD RD - Vout You may have already noticed that the common source amplifier circuit is basically the same as the NMOS RTL inverter, just used for different purposes. The slope of the inverter VTC (Vout-Vin curve) is also the small- signal voltage gain of the common source amplifier. Assume VDD = 5V and Vin M₁ Vthn 0.7 V for the NMOS, use PSPICE to simulate the VTC (sweep from 0 to 5 V) of the common source amplifier for the following conditions: (a) Fix RD = 100 kN, L = 1 µm, W = 1 μm. Vary kn² = 20, 100, and 500 μА/V². (b) Fix kn' = 100 µA/V², R₁ = 100 kQ, L = 1 μm. Vary W = 1, 5, and 50 μm. (c) Fix kn' = 1 100 μA/V², L = 1 µm, W= 1 µm. Vary RD = 10 k2, 100 kQ, 1 MQ. Compare the slopes of the VTCs (which correspond to the voltage gains of the amplifiers) you obtained from the various conditions in a-c and explain your results.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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J VDD RD - Vout You may have already noticed that the common source amplifier circuit is basically the same as the NMOS RTL inverter, just used for different purposes. The slope of the inverter VTC (Vout-Vin curve) is also the small- signal voltage gain of the common source amplifier. Assume VDD = 5V and Vin M₁ Vthn 0.7 V for the NMOS, use PSPICE to simulate the VTC (sweep from 0 to 5 V) of the common source amplifier for the following conditions: (a) Fix RD = 100 kN, L = 1 µm, W = 1 μm. Vary kn² = 20, 100, and 500 μА/V². (b) Fix kn' = 100 µA/V², R₁ = 100 kQ, L = 1 μm. Vary W = 1, 5, and 50 μm. (c) Fix kn' = 1 100 μA/V², L = 1 µm, W= 1 µm. Vary RD = 10 k2, 100 kQ, 1 MQ. Compare the slopes of the VTCs (which correspond to the voltage gains of the amplifiers) you obtained from the various conditions in a-c and explain your results.
Transcribed Image Text:J VDD RD - Vout You may have already noticed that the common source amplifier circuit is basically the same as the NMOS RTL inverter, just used for different purposes. The slope of the inverter VTC (Vout-Vin curve) is also the small- signal voltage gain of the common source amplifier. Assume VDD = 5V and Vin M₁ Vthn 0.7 V for the NMOS, use PSPICE to simulate the VTC (sweep from 0 to 5 V) of the common source amplifier for the following conditions: (a) Fix RD = 100 kN, L = 1 µm, W = 1 μm. Vary kn² = 20, 100, and 500 μА/V². (b) Fix kn' = 100 µA/V², R₁ = 100 kQ, L = 1 μm. Vary W = 1, 5, and 50 μm. (c) Fix kn' = 1 100 μA/V², L = 1 µm, W= 1 µm. Vary RD = 10 k2, 100 kQ, 1 MQ. Compare the slopes of the VTCs (which correspond to the voltage gains of the amplifiers) you obtained from the various conditions in a-c and explain your results.
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