(j) Mean Absolute Deviation (k) Variance (l) Standard Deviation
Q: Score Lxi> 2
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Q: til
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Q: standard error.
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(j)
(k) Variance
(l) Standard Deviation
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- Interpret the Z score for a student who scored an 91 on an exam that had a mean of 86 and a standard deviation of 5. One mean above the standard deviation One standard deviation above the mean One standard deviation below the mean One mean below the standard deviationGrowth of bacteria culture after one week, represented by its size, is known to follow lognormal distribution with mean of 2 and variance of 0.2. What is the upper and lower quartile of the size of the culture after one week?Statistical Physics
- Range Mean Absolute Deviatio Sample Standar d. Deviatio Sample VarianceIntegrate x2 between -1 and 3 between using both the stone throwing approach and the mean value approach. For m=1 & N=1000, what do you observe if you plot N vs calculated value of the function for both methods? For N=102, 103,104, 105, 106 and m=16 plot the N vs absolute error for both methods. What relationship fits this distribution of points? Comment on what you observe Now plot N against the Standard Deviation (the Variance) for both methods and comment on what you observe.Scores on a history test have an average of = 70 with standard deviation of 5. What is the z-score for a student who earned a 65 on the test? What is the coefficient of variation? 2. The annual salaries of employees in a large company are approximately normally distributed with a mean of $70,000 and a standard deviation of $30,000. (6 points) What percent of people earn less than $40,000? What percent of people earn more than $85,000? What percent of people earn between $40,000 and $85,000? 3. Assume women’s heights follow a normal distribution with a mean of u = 64.5 inches and a standard deviation of 2.5 inches. Find the probability that a sample of 14 women have a mean height greater than 65 inches.
- (Q2) Please answer correctly and fastly. ThanksAssuming variance > 1, which of the following must be true? The sample variance is calculated based on the sample size rather than the degrees of freedom The data are normally distributed Standard deviation < variance The model will explain more than 50% of the variance of the dependent variable