JJul 14, 2024Moving to another question will save this response.Question 1Which of the following is expected to have a low dielectric constant?O CH3CNNaCl(aq)H2SCH3CH2CH2CH2CH3CF3CO2HCoInEAMquestMemeDownloadMay 21, 232A, 425YMHuss May 16, 2024, 5:05 PM@W+80F3F4#3$4%905F5MacBook Air66ΛAADIIF6F7F8LLERTY&27כ80 *961DDF9

Approach to solving the question:Rational Detailed explanation:To determine which of the given…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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AuBr(s) + 2 CN– (aq) ⇄ [Au(CN)2]– (aq) + Br– (aq) Given: Keq = 2.02 x 1033 Ksp for AuBr is 9.8 x 10–6, Solve for the Kf of [Au(CN)2]–
Ligands like BAL and enterobactin are important in medical treatments for heavy metal poisoning. However, chelation therapies can disrupt the normal concentration of ions in the body, leading to serious side effects, so researchers are searching for new chelation drugs. One drug that has been developed is dimercaptosuccinic acid (DMSA), as shown. Identify which atoms in this molecule could act as donor atoms.
1. Calculate the stability field of gibbsite Al(OH)3 versus its aqueous species on the basis of the below listed four equilibrium equations. Al(OH)3(gibbsite) + 3H+ = A13+ + ЗН20() Ks0 = 109.36 Al" + H,O(1) = Al(OH)** + H* Al3* + 2H2O(1) = Al(OH)2* + 2H* Al³* + 4H2O(1) = Al(OH)4¯ + 4H* K. sl =104.99 K s,2 =10-10.13 K s,4 =10-22.05 2. Two solutions have the following activities: 0.02 mol L-' F and 0.01 mol L' Ca²+ 0.0001 molL-'F and 0.0002 mol L' Ca²+ i. ii. Calculate the saturation indices of the solutions versus fluorite (pKsp = 10.6) and how much fluorite would precipitate or dissolve in order to achieve equilibrium. -
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Using the Born-Haber cycle, the AH°f of KBr is equal to A) AH°f [K (g)] - AH°f [Br (g)] - I1(K) - E(Br) - AHlattice B) AH°f [K (g)] + AH°f [Br (g)] + I₁ (K) + E(Br) + AHlattice C) AH°f [K (g)] - AH°f [Br (g)] + I1 (K) – E(Br) + AHlattice D) AH°f [K (g)] + AH°f [Br (g)] - I1 - E(Br) + AHlattice E) AH°f [K (g)] + AH°f [Br (g)] + I1 (K) + E(Br) - AHlattice
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