IZJWY A 0.11 kg bullet moving 212_m/s hits a 6.1 kg block of wood at rest. If the bullet becomes embedded in the wood (and if the block of wood is free to move), what is the speed of the system immediately after the impact? What percent of the kinetic energy is lost due to the impact? 4. speed A. 3.378_m/s D. 3.537_m/s B. 3.755 m/s E. 3.227_m/s C. 4.11 m/s F. 3.956 m/s 1--1 94.76 percent 117.60 percent 108.20 percent IZIWR 5. percent A. B. C. 1--1 98.23 percent 113.10 percent 103.70 percent DEE E. F.

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**Physics Problems: Collisions and Kinetic Energy**

**Problem 4:**
A 0.11 kg bullet moving at 212 m/s hits a 6.1 kg block of wood at rest. If the bullet becomes embedded in the wood (and if the block of wood is free to move), what is the speed of the system immediately after the impact? What percent of the kinetic energy is lost due to the impact?

**Options for speed:**
A. 3.378 m/s
B. 3.755 m/s
C. 4.11 m/s
D. 3.537 m/s
E. 3.227 m/s
F. 3.956 m/s

**Problem 5:**
What percent of the kinetic energy is lost due to the impact?

**Options for percent:**
A. 98.23 percent
B. 113.10 percent
C. 103.70 percent
D. 94.76 percent
E. 117.60 percent
F. 108.20 percent

**Problem 6:**
A can of Coke moving at 18.1 m/s toward the right (the positive direction) collides with a can of Pepsi moving at 4.36 m/s toward the left, and both cans are badly crunched. If the final velocity of the can of Coke is 5.63 m/s still toward the right, then what is the final velocity of the can of Pepsi? Assume the two cans have equal masses.

**Options for final velocity of the can of Pepsi:**
A. 6.26 m/s
B. -6.37 m/s
C. -2.88 m/s

**Explanation:**
This set of problems requires the application of the principles of conservation of momentum and energy. The first problem involves a collision between a bullet and a block of wood, asking you to determine their combined speed post-collision and the percentage of kinetic energy lost. The second problem is about a collision between two cans, requiring determination of the final velocity of one can given the conditions described.

These problems can be solved using the respective formulas:
1. Conservation of Momentum:
   \[
   m_1 v_{1i} + m_2 v_{2i} = (m_1 + m_2) v_f
   \]
2. Kinetic Energy:
   \[
   KE = \frac
Transcribed Image Text:**Physics Problems: Collisions and Kinetic Energy** **Problem 4:** A 0.11 kg bullet moving at 212 m/s hits a 6.1 kg block of wood at rest. If the bullet becomes embedded in the wood (and if the block of wood is free to move), what is the speed of the system immediately after the impact? What percent of the kinetic energy is lost due to the impact? **Options for speed:** A. 3.378 m/s B. 3.755 m/s C. 4.11 m/s D. 3.537 m/s E. 3.227 m/s F. 3.956 m/s **Problem 5:** What percent of the kinetic energy is lost due to the impact? **Options for percent:** A. 98.23 percent B. 113.10 percent C. 103.70 percent D. 94.76 percent E. 117.60 percent F. 108.20 percent **Problem 6:** A can of Coke moving at 18.1 m/s toward the right (the positive direction) collides with a can of Pepsi moving at 4.36 m/s toward the left, and both cans are badly crunched. If the final velocity of the can of Coke is 5.63 m/s still toward the right, then what is the final velocity of the can of Pepsi? Assume the two cans have equal masses. **Options for final velocity of the can of Pepsi:** A. 6.26 m/s B. -6.37 m/s C. -2.88 m/s **Explanation:** This set of problems requires the application of the principles of conservation of momentum and energy. The first problem involves a collision between a bullet and a block of wood, asking you to determine their combined speed post-collision and the percentage of kinetic energy lost. The second problem is about a collision between two cans, requiring determination of the final velocity of one can given the conditions described. These problems can be solved using the respective formulas: 1. Conservation of Momentum: \[ m_1 v_{1i} + m_2 v_{2i} = (m_1 + m_2) v_f \] 2. Kinetic Energy: \[ KE = \frac
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