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ix-sided dice ommon valu

ix-sided dice ommon valu

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Hello can you please help me with this problem because I don't understand it and i don't understand the parts as well can you please do this step by step and can you label the parts as well.

 

Can you please do this step by step and can you label the parts as well.

2.1-7. Let a random experiment be the casting of a pair of fair six-sided dice and let X equal the smaller of the outcomes if they are different and the common value if they are equal. a. With reasonable assumptions, find the pmf of X. b. Draw a probability histogram of the pmf of X. c. Let Y equal the range of the two outcomes (i.e., the absolute value of the difference of the largest and the smallest outcomes). Determine the pmf g(y) of Y for y = 0, 1, 2, 3, 4, 5.
Transcribed Image Text:2.1-7. Let a random experiment be the casting of a pair of fair six-sided dice and let X equal the smaller of the outcomes if they are different and the common value if they are equal. a. With reasonable assumptions, find the pmf of X. b. Draw a probability histogram of the pmf of X. c. Let Y equal the range of the two outcomes (i.e., the absolute value of the difference of the largest and the smallest outcomes). Determine the pmf g(y) of Y for y = 0, 1, 2, 3, 4, 5.
Expert Solution
Step 1: The sample space of rolling two fair dice with equal to sign shows the minimum:
Consider a random experiment, be the roll of two fair six-sided dice, and consider Error converting from MathML to accessible text. to be the minimum of the two outcomes, the corresponding probability is determined using probability distribution.


The sample space of rolling two fair dice with equal to sign shows the minimum:


In the sample space, there are 36 possible outcomes. As a result, here is the X diagram:

 here as there are total 36 outcome by xasting two dice.

P(X=1) =11/36    (as 1 will be least outcome ; 11 time it appear at least once out of 36 rolls)

P(X=2) =9/36   ( except with 1, it is the least outcome)


The sample space of rolling two fair dice with equal to sign shows the minimum:

image
In the sample space, there are 36 possible outcomes. As a result, here is the X diagram:


P(X=3)=7/36

P(X=4) =5/36

P(X=5)=3/36

P(X=6) =1/36



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