Critical flaw size corresponds to the transition between general yielding and fast fracture. If the fracture toughness of a high-strength steel can be increased by 55 % (from 100 to 155 MPa /m) without changing its yield strength of 1270 MPa, by what percentage is its critical flaw size changed?Express your answer to three significant figures.IVE ΑΣΦ ↓↑ vec 6% increase = 4.33Submit Previous Answers Request AnswerX Incorrect; Try Againovide Feedback?

Design stress=1270MPa To find % increase in flaw size

Answered: IVE| ΑΣΦ increase = 4.33 ubmit Previous…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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QUESTION 4 Solve the following differential equation in Matlab using ode45.m. Use time interval of 0.1 second. (Don't use options in ode45 to change teh tolerance.) do (t) dt - cos = sint 0(0)=0. What is e(t=4.1)? ○ 0.871 -0.212 1.44 1.28 2.01 3.19
P1 + as 2g pg P2 +z, + hpompa.f L V² + z2 + h¢arbing +hx,toplam_hxsûrekli= f. pg 'D´2g Wmil hỵ̟toplam= hx,sûrekli + hx,yerel Nsp = (gH)³/4 hkyerel = 2g Протра 一()-)图)第-(=)G) 5 HB Wmil,B _ PB (WB PAlwa) DA Wmil,A WR (DB wWm/2 Ns = %3D WA (DA HA Wmil = PgHỳntarbin p1/2(gH)5/4 Wmil = prwv(V; – rw)(1 – cosß) At the best efficiency point with the experiments on the A turbine DA= 72 cm, HA= 20 m, V = 50 m/s, PA= 998 kg/m³, na= 205 revolution per minute , Wmila= 9 MW values have been obtained. PB= 998 kg/m³, HB= 65 m, nâ= 185 A new B turbine will be designed. According to this ; a) B is the volumetric flow of the turbine (VR) (m/s) find as. c) Find the specific speed of turbine B. b) Find the power of turbine B. (Wmil.B) 2.5 d) Find the diameter of turbine B. 285 245.3 MW 3,5 120 cm 361 211,5 MW O 2.8 156 cm 180 190 MW O 2,1 144 cm 255 182,7 MW O 31 O 104 cm 375 250 MW O 95 am O O
How do integrate to get fbd= 15/28?
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IKT f 327 DXD 187 S 487
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Is this Correct?
Q15
T(t) 0(t) K = 5 N-m/rad D Given the system shown, if the value of D is 1.04 N-m-s/rad, then the value of J that yield 10% overshoot is: Select one: O a. None of the mentioned answers O b. 0.065 O c. 0.619 O d. 0.155
Question C Work from point 0 to when graph hits -2 again
2345 + 124508 + A2B34H16 = _2

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IVE| ΑΣΦ increase = 4.33 ubmit Previous Answers Request Answer Incorrect; Try Again edback jcam 4 ? %