IV characteristics curve of an NPN BJT in common emitter configuration is shown in Fig below. Obtain Ic, VCE and IB for the points A, B and C on the curve. Which region does the BJT operate for each point? Collector current 10 mA A 5 mA 0 A 3. VB = OV, Vc = -2V, VE = 1V. 4. VB = -4V, Vc = 3V, VE = 2V OV 5 V 900 VCE 10 V = 100 μα IB= 80 μA Tg = 60 μA C IB = 40 μA B IB= 20 μA| 15 V The terminal voltages of an NPN/PNP BJT are given below. Determine the region the BJT is operating for each sets of terminal voltages. 1. VB= 2V, Vc = -2V, VE = OV. 2. VB = -2V, Vc = -2V, VE = -3V.
IV characteristics curve of an NPN BJT in common emitter configuration is shown in Fig below. Obtain Ic, VCE and IB for the points A, B and C on the curve. Which region does the BJT operate for each point? Collector current 10 mA A 5 mA 0 A 3. VB = OV, Vc = -2V, VE = 1V. 4. VB = -4V, Vc = 3V, VE = 2V OV 5 V 900 VCE 10 V = 100 μα IB= 80 μA Tg = 60 μA C IB = 40 μA B IB= 20 μA| 15 V The terminal voltages of an NPN/PNP BJT are given below. Determine the region the BJT is operating for each sets of terminal voltages. 1. VB= 2V, Vc = -2V, VE = OV. 2. VB = -2V, Vc = -2V, VE = -3V.
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Transcribed Image Text:IV characteristics curve of an NPN BJT in common emitter configuration is shown in Fig below.
Obtain Ic, VCE and IB for the points A, B and C on the curve. Which region does the BJT operate for
each point?
Collector current
10 mA
A
5 mA
0 A
OV
5 V
1. VB = 2V, Vc = -2V, VE = OV.
2. VB = -2V, Vc = -2V, VE = -3V.
3. VB =
OV, Vc = -2V, VE = 1V.
4. VB = -4V, Vc = 3V, VE = 2V
900
VCE
10 V
= 100 μα
IB = 80 μA
Tg = 60 μA
C
1B = 40 μA
B
IB= 20 μA|
15 V
The terminal voltages of an NPN/PNP BJT are given below. Determine the region the BJT is operating
for each sets of terminal voltages.
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