ium 6. When potassium chloride reacts with oxygen under the right conditions, potassium chloride is formed. Given the heat formation of KCl(s) (-435.9) and KCIO3(s) (-391.4). Calculate the standard molar enthalpy of reaction for 2KCl(s) + 302(g) à 2KCIO3(s) FORMULA: SOLUTION: FINAL ANSWER:

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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FORMULA:
SOLUTION:
Substance
FINAL ANSWER:
A Hof of Some Common Substances
C (graphite)
CO (g)
CO₂(g)
C₂H5OH (1)
CaCO3 (s)
CaO (s)
Fe₂O3 (s)
H₂O(g)
5. Calcium carbonate decomposes at high
temperature to form carbon dioxide and calcium
oxide. Determine the heat of reaction.
CaCO3(s) à CO2(g) + CaO (s)
Specific Heat
A Hof (kJ/mol)
0
-110.5
-393.5
-277.7
-1206.9
-635.6
-824.2
-241.8
Substance
H₂O (
N₂(g)
NaCl (s)
NH3(g)
NO (g)
NO₂ (g)
N₂O(g)
O₂ (g)
Specific Heat
AH% (kJ/mol)
-285.8
0
FORMULA:
6. When potassium chloride reacts with oxygen
under the right conditions, potassium chloride is
formed. Given the heat formation of KCl) (-435.9)
and KCIO3(s) (-391.4). Calculate the standard
molar enthalpy of reaction for
2KCl(s) + 302(g) à 2KCIO3(s)
-411.2
-46.3
90.29
33.85
81.56
0
SOLUTION:
FINAL ANSWER:
Transcribed Image Text:FORMULA: SOLUTION: Substance FINAL ANSWER: A Hof of Some Common Substances C (graphite) CO (g) CO₂(g) C₂H5OH (1) CaCO3 (s) CaO (s) Fe₂O3 (s) H₂O(g) 5. Calcium carbonate decomposes at high temperature to form carbon dioxide and calcium oxide. Determine the heat of reaction. CaCO3(s) à CO2(g) + CaO (s) Specific Heat A Hof (kJ/mol) 0 -110.5 -393.5 -277.7 -1206.9 -635.6 -824.2 -241.8 Substance H₂O ( N₂(g) NaCl (s) NH3(g) NO (g) NO₂ (g) N₂O(g) O₂ (g) Specific Heat AH% (kJ/mol) -285.8 0 FORMULA: 6. When potassium chloride reacts with oxygen under the right conditions, potassium chloride is formed. Given the heat formation of KCl) (-435.9) and KCIO3(s) (-391.4). Calculate the standard molar enthalpy of reaction for 2KCl(s) + 302(g) à 2KCIO3(s) -411.2 -46.3 90.29 33.85 81.56 0 SOLUTION: FINAL ANSWER:
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