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Item 2. Aeroman shoots an arrow vertically at a speed of 180 km/hr. Calculate the maximum height 6 the arrow can reach from the ground and the
total time from being fired until it falls to the ground. (Air resistance is not taken and the Earth's value is always constant equal to
9.81 mV/s)
2.) v=V, +at, 3.) v² = v5 +2a(s – s,), 4) s = 5,+Vgt +- at*

Expert Solution

Step 1

Given,

Initial velocity v₀ = 180 km/hr=50 m/s

g=9.81 mV/s

For Maximum height v=0

initial position is ground, s₀ =0

$v^{2} = {v_{0}}^{2} + 2 a (s - s_{0}) v^{2} = {v_{0}}^{2} + 2 g (s - s_{0}) 0 = {(180)}^{2} + 2 \times (-) 9.81 (s - 0) s = \frac{50^{2}}{2 \times 9.81} = 127.42 m$

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