An object is thrown upward at a speed of 55 feet per second by a machine from a height of 18 feetoff the ground. The height of the object after t seconds can be found using the equationh(t)16t + 55t + 18. Give all numerical answers to 2 decimal places.When will the object reach the ground?units:When will the object reach its maximum height?units:What is its maximum height?units:Question Help: DVideoSubmit Question

initial velocity u = 55ft/sec initial position = 18ft h(t)=-16t2+55t+18 ---------eqn(1)

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