it takes a solution 37.00ml of a 0.150 M solution of potassium hydroxide to completely react with 45.00 mL of sulfuric acid solution. Calculate the molarity of the sulfuric acid solution. Write the baleced chemical equation. b.) how many ml of the 0.150M potassium hydroxide solution would you need to make 375.0ml of a 0.0888 M solution of potassium hydroxide?
it takes a solution 37.00ml of a 0.150 M solution of potassium hydroxide to completely react with 45.00 mL of sulfuric acid solution. Calculate the molarity of the sulfuric acid solution. Write the baleced chemical equation. b.) how many ml of the 0.150M potassium hydroxide solution would you need to make 375.0ml of a 0.0888 M solution of potassium hydroxide?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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a.) it takes a solution 37.00ml of a 0.150 M solution of potassium hydroxide to completely react with 45.00 mL of sulfuric acid solution. Calculate the molarity of the sulfuric acid solution. Write the baleced chemical equation.
b.) how many ml of the 0.150M potassium hydroxide solution would you need to make 375.0ml of a 0.0888 M solution of potassium hydroxide?
Expert Solution
a) calculation
- Given information:
Volume of KOH is found to be 37.00 ml = 0.037 L.
Molarity of KOH is found to be 0.150 M
Volume of sulphuric acid if found to be 45.00ml = 0.045L.
Calculation:
The balanced equation can be written as: H2SO4 + 2KOH → K2SO4 + 2H2O
From the equation it is clear that 1 mol sulphuric acid nedds 2 mols of KOH.
Number of moles of KOH is found to be
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