It takes 24.05 mL of 0.952 M NAOH to titrate a 15.00 ml sample of white vinegar (i.e. HC2H3O2).НС-Нз02(аq) + NaOH(aq) — Hz0() + NaC,Hҙ02(aq)2.а.What is the molar concentration of the vinegar?b. If the density of the solution is 1.05 g/mL, what is the percent by mass of the vinegar in thesolution?

Given data: Molarity of NaOH = 0.952 M Volume of NaOH = 24.05 mL Volume of vinegar = 15.00 mL…

It takes 24.05 mL of 0.952 M NaOH to titrate a 15.00 mL sample of white vinegar (i.e. HC2H3O2). HC,H302(aq) + NaOH(aq) → H20(1) + NaC,H302(aq) 2. а. What is the molar concentration of the vinegar? b. If the density of the solution is 1.05 g/mL, what is the percent by mass of the vinegar in the solution?

It takes 24.05 mL of 0.952 M NaOH to titrate a 15.00 mL sample of white vinegar (i.e. HC2H3O2). HC,H302(aq) + NaOH(aq) → H20(1) + NaC,H302(aq) 2. а. What is the molar concentration of the vinegar? b. If the density of the solution is 1.05 g/mL, what is the percent by mass of the vinegar in the solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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