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It shows that limn→∞|bn|= 0 if and only if limn→∞bn= 0. However, it gives an example of a succession{cn} n ∈ Ntal that limn→∞|cn|=L and L other than 0 but limn→∞cn does not exist (you must argue why such a limit does not exist) Note: the demonstration must be non-numeric, the example must be numerical and must be proven because the cn limit does not exist

It shows that limn→∞|bn|= 0 if and only if limn→∞bn= 0. However, it gives an example of a succession{cn} n ∈ Ntal that limn→∞|cn|=L and L other than 0 but limn→∞cn does not exist (you must argue why such a limit does not exist) Note: the demonstration must be non-numeric, the example must be numerical and must be proven because the cn limit does not exist

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 54E
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It shows that limn→∞|bn|= 0 if and only if limn→∞bn= 0. However, it gives an example of a succession{cn} n ∈ Ntal that limn→∞|cn|=L and L other than 0 but limn→∞cn does not exist (you must argue why such a limit does not exist)

Note: the demonstration must be non-numeric, the example must be numerical and must be proven because the cn limit does not exist

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