It is stated in the text that special relativity must be used to calculate the de Broglie wavelength of electrons in an electron microscope. Let us discover how much of an effect relativity has. Consider an electron that has been accelerated through a potential difference of 1.5x105 V. Part A Using the Newtonian (non-relativistic) expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength? Express your answer using two significant figures. A = ΜΕ ΑΣΦ Submit Request Answer Part B ? m The de Broglie wavelength is λ=h/p, but the momentum of a relativistic particle is not mv. Using the relativistic expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength? Express your answer using two significant figures. ΜΕ ΑΣΦ λ = Submit Request Answer ? m

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It is stated in the text that special relativity must be
used to calculate the de Broglie wavelength of
electrons in an electron microscope. Let us
discover how much of an effect relativity has.
Consider an electron that has been accelerated
through a potential difference of 1.5x105 V.
Part A
Using the Newtonian (non-relativistic) expressions for kinetic energy and momentum, what is the electron's de Broglie
wavelength?
Express your answer using two significant figures.
A =
ΜΕ ΑΣΦ
Submit
Request Answer
Part B
?
m
The de Broglie wavelength is λ=h/p, but the momentum of a relativistic particle is not mv. Using the relativistic
expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength?
Express your answer using two significant figures.
ΜΕ ΑΣΦ
λ =
Submit
Request Answer
?
m
Transcribed Image Text:It is stated in the text that special relativity must be used to calculate the de Broglie wavelength of electrons in an electron microscope. Let us discover how much of an effect relativity has. Consider an electron that has been accelerated through a potential difference of 1.5x105 V. Part A Using the Newtonian (non-relativistic) expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength? Express your answer using two significant figures. A = ΜΕ ΑΣΦ Submit Request Answer Part B ? m The de Broglie wavelength is λ=h/p, but the momentum of a relativistic particle is not mv. Using the relativistic expressions for kinetic energy and momentum, what is the electron's de Broglie wavelength? Express your answer using two significant figures. ΜΕ ΑΣΦ λ = Submit Request Answer ? m
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