A. We again consider the photoelectric effect apparatus and will assume that the light source is on.Monochromaticlight sourceEvacuatedtubeHAV'ВLet I, represent the ammeter reading with no battery in the circuit.1. Is I1, the current when there is one battery in the circuit, greater than, less than or equal to Io? Explain.2. A second battery is added in series with the first; both batteries have the same orientation. Rank I, I₁, and I₂ (the current when there are two batteries in the circuit)according to magnitude, from largest to smallest. Explain.3. Suppose additional batteries were inserted in the same manner. Would the current increase with each addition? If so, is there a limit to the amount of current that can beproduced? Explain.4. Is it possible to use batteries to decrease the current? If so, show how to connect the batteries and sketch some possible paths of electrons.B5. Could batteries be used to produce a constant clockwise flow of electrons (i.e., a negative ammeter reading)? Justify your answer.

Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first three sub-parts for you. To get remaining sub-part solved please repost the complete question and mention the sub parts to be solved.” We are given light striking metal surface. We see what is called photo electric effect. This effect shows particle nature of light. Photons transfer their energy completely to electrons on the surface atoms.We are given that Io is the photocurrent when there is no battery attached. Part 1. We are connecting a battery. This battery has some voltage. Now after applying battery, current is I1. The voltage is applied as in the direction of photocurrent. Hence it increases the voltage of plates and hence photocurrent increases. Hence, I1>Io. Part 2. Now second battery is also added with same orientation. Hence the applied voltage increases which increases the potential of plates in the tube. Hence, it facilitates the flow of electrons. Hence current further increases. Since now current has become I2. Hence, I2>I1>Io Part 3. More battery increases voltage which increase photocurrent. But there is a saturation point of photocurrent. This is because number of electrons emitted depends on the intensity of light. Since number of electrons which reach the plate decides the current, all the electrons ejected have reached the plate for certain potential and hence saturation occurs.

Answered: A. We again consider the photoelectric…