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4uf 2uf The net capacitance in the circuit shown above is B. 6.0 µF. A. 8.0 µF. C. 4.0 µF. D. 2.0 µF.

4uf 2uf The net capacitance in the circuit shown above is B. 6.0 µF. A. 8.0 µF. C. 4.0 µF. D. 2.0 µF.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Physics Problems on Plane Mirrors and Capacitance #### Question 9: **Problem Statement:** When a plane mirror at which a ray is incident is rotated through an angle \(\theta\), the reflected ray will be rotated through: - A. \( \frac{1}{2} \theta \) - B. \( \theta \) - C. \( 2 \theta \) - D. \( 3 \theta \) #### Question 10: **Problem Statement:** The net capacitance in the circuit shown below is: **Circuit Diagram:** - A circuit is provided with three capacitors. - Two capacitors are in parallel each with a capacitance of 2 μF. - Another capacitor with a capacitance of 4 μF is in series with the parallel combination. - Terminal points are marked as \( P \) and \( O \). **Circuit Diagram Explanation:** - The circuit consists of three capacitors. The first two capacitors, each with a capacitance of 2 μF, are connected in parallel. - A third capacitor with a capacitance of 4 μF is connected in series with the parallel combination. **Possible Answers:** - A. \( 8.0 \, \mu F \) - B. \( 6.0 \, \mu F \) - C. \( 4.0 \, \mu F \) - D. \( 2.0 \, \mu F \) **Hint for Students:** To solve the net capacitance in the circuit, remember: 1. For capacitors in parallel: \( C_{parallel} = C_1 + C_2 \) 2. For capacitors in series: \( \frac{1}{C_{series}} = \frac{1}{C_1} + \frac{1}{C_2} \) Calculate the capacitance step-by-step using these formulae to find the net capacitance.
Transcribed Image Text:### Physics Problems on Plane Mirrors and Capacitance #### Question 9: **Problem Statement:** When a plane mirror at which a ray is incident is rotated through an angle \(\theta\), the reflected ray will be rotated through: - A. \( \frac{1}{2} \theta \) - B. \( \theta \) - C. \( 2 \theta \) - D. \( 3 \theta \) #### Question 10: **Problem Statement:** The net capacitance in the circuit shown below is: **Circuit Diagram:** - A circuit is provided with three capacitors. - Two capacitors are in parallel each with a capacitance of 2 μF. - Another capacitor with a capacitance of 4 μF is in series with the parallel combination. - Terminal points are marked as \( P \) and \( O \). **Circuit Diagram Explanation:** - The circuit consists of three capacitors. The first two capacitors, each with a capacitance of 2 μF, are connected in parallel. - A third capacitor with a capacitance of 4 μF is connected in series with the parallel combination. **Possible Answers:** - A. \( 8.0 \, \mu F \) - B. \( 6.0 \, \mu F \) - C. \( 4.0 \, \mu F \) - D. \( 2.0 \, \mu F \) **Hint for Students:** To solve the net capacitance in the circuit, remember: 1. For capacitors in parallel: \( C_{parallel} = C_1 + C_2 \) 2. For capacitors in series: \( \frac{1}{C_{series}} = \frac{1}{C_1} + \frac{1}{C_2} \) Calculate the capacitance step-by-step using these formulae to find the net capacitance.
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