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It is known that only 0.1% of students at a local university does not own a laptop. A survey was conducted, and out of 2000 university students interviewed what is the probability that the number of students who does not own a laptop is at most 2? O a. Y – B(2000, 0.001) O b. X~B(2000, 0.001) OC. X~P(2) O d. P(X ≥2)=1-P(X ≤ 1) P(X ≤2) = P(X = 0) + P(X = 1) P(X ≤2) = P(X = 0) + P(X = 1) + P(X = 2) X~P(2) P(X ≤2) = P(X= 0) + P(X=1)

It is known that only 0.1% of students at a local university does not own a laptop. A survey was conducted, and out of 2000 university students interviewed what is the probability that the number of students who does not own a laptop is at most 2? O a. Y – B(2000, 0.001) O b. X~B(2000, 0.001) OC. X~P(2) O d. P(X ≥2)=1-P(X ≤ 1) P(X ≤2) = P(X = 0) + P(X = 1) P(X ≤2) = P(X = 0) + P(X = 1) + P(X = 2) X~P(2) P(X ≤2) = P(X= 0) + P(X=1)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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It is known that only 0.1% of students at a local university does not own a laptop. A survey was conducted, and out of 2000 university students interviewed what is the probability that the number of students who does not own a laptop is at most 2? O a. X~B(2000, 0.001) O b. X~B(2000, 0.001) OC. X~P(2) O d. X~P(2) P(X ≥2)=1-P(X ≤ 1) P(X ≤2) = P(X = 0) + P(X = 1) P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2) P(X ≤2) = P(X = 0) + P(X =1)
Transcribed Image Text:It is known that only 0.1% of students at a local university does not own a laptop. A survey was conducted, and out of 2000 university students interviewed what is the probability that the number of students who does not own a laptop is at most 2? O a. X~B(2000, 0.001) O b. X~B(2000, 0.001) OC. X~P(2) O d. X~P(2) P(X ≥2)=1-P(X ≤ 1) P(X ≤2) = P(X = 0) + P(X = 1) P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2) P(X ≤2) = P(X = 0) + P(X =1)
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