It is just a discussion problem without calculation Two identical masses are attached to frictionless pulleys by very light strings wrapped around the rim of the pulley and are released from rest. Both pulleys have the same mass and same diameter, but one is solid and the other is a hoop. As the masses fall, in which case is the tension in the string greater, or is it the same in both cases? Justify your answer.

It is just a discussion problem without calculation Two identical masses are attached to frictionless pulleys by very light strings wrapped around the rim of the pulley and are released from rest. Both pulleys have the same mass and same diameter, but one is solid and the other is a hoop. As the masses fall, in which case is the tension in the string greater, or is it the same in both cases? Justify your answer.

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter8: Rotational Motion

Section8.2: Rotational Dynamics

Problem 27PP

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Two identical masses are attached to frictionless pulleys by very light strings wrapped around the rim of the pulley and are released from rest. Both pulleys have the same mass and same diameter, but one is solid and the other is a hoop. As the masses fall, in which case is the tension in the string greater, or is it the same in both cases? Justify your answer.
help pls asap not in scientific notation pls
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A mass M of 3.60E-1 kg slides inside a hoop of radius R=1.60 m with negligible friction. When M is at the top, it has a speed of 5.21 m/s. Calculate the size of the force with which the M pushes on the hoop when M is at an angle of 41.0°.
Two blocks of mass m1 = 3 kg and m2 =7 kg are connected by a massless string over a pulley with radius r= 0.25 m and masa M= 9 kg . There aren't friction forces in inclined planes . The directions of acceleration a and angular acceleration a are güven in Figure. (a) Draw free-body diagram. (b) Find the linear acceleration . (c) Find the angular acceleration. (d) Find tane tensions in the string. ( 1=1\2 Mr^2 , g=9.8 m/s^2 sin53=0.8 cos53 =0.6 )
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