It has long been stated that the mean temperature of humans is 98.6°F. However, two researchers currently involved in the subject thought that the meantemperature of humans is less than 98.6°F. They measured the temperatures of 56 healthy adults 1 to 4 times daily for 3 days, obtaining 250 measurements. Thesample data resulted in a sample mean of 98.3°F and a sample standard deviation of 1°F. Use the P-value approach to conduct a hypothesis test to judge whetherthe mean temperature of humans is less than 98.6°F at the a = 0.01 level of significance. State the hypotheses.Họ: H= 98.6°FH: H < 98.6°FFind the test statistic.6-0(Round to two decimal places as needed.)The P-value is(Round to three decimal places as needed.)What can be concluded?What can be concluded?A. Reject Ho since the P-value is not less than the significance level.B. Reject Ho since the P-value is less than the significance level.C. Do not reject Ho since the P-value is not less than the significance level.OD. Do not reject Ho since the P-value is less than the significance level.

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Answered: It has long been stated that the mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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When 40 people used the Weight Watchers dies for one year, their mean weight loss was 3.0 lb and the standard deviation was 4.9 lb. Use a 0.01 significance level to test the claim that the mean weight loss is greater than 0. (Show the solution) A. The null hypothesis is i. The mean weight loss is equal to 0. ii. The mean weight loss is not equal to 0. iii. The mean weight loss is greater than 0. iv. The mean weight loss is less than 0. B. The computed t-test statistic is i. 4.468 ii. 4.977 iii. 3.872 iv. 3.391 C. The critical/tabular t-test statistic is i. 2.426 ii. 1.684 iii. 1.685 iv. 2.423 D. Decision rule: i. Do not reject the null hypothesis. ii. Reject the null hypothesis. E. The final conclusion is i. The mean weight loss is not equal to 0 therefore Weight Watchers is effective. ii. The mean weight loss is less than 0 therefore Weight Watchers is not effective. iii. The mean weight loss is equal to 0 therefore Weight Watchers…
It has long been stated that the mean temperature of humans is 98.6°F. However, two researchers currently involved in the subject thought that the mean temperature of humans is less than 98.6°F. They measured the temperatures of 50 healthy adults 1 to 4 times daily for 3 days, obtaining 225 measurements. The sample data resulted in a sample mean of 98.4°F and a sample standard deviation of 1°F. Use the P-value approach to conduct a hypothesis test to judge whether the mean temperature of humans is less than 98.6°F at the oa = 0.01 level of significance. State the hypotheses. Ho: H = 98.6°F H1: H < 98.6°F Find the test statistic. tn = - 3.00 (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.)
A researcher tests whether listening to music while taking an exam has any effect. The population mean of people taking an exam while not listening to music is 50, with a standard deviation of 12. The researcher tests a sample of 57 people who listen to music while taking an exam and they produce a mean of 54.36. Using a one-tailed test with a p value of .05, the critical value is -1.65 and 1.65. Make a decision about your hypothesis.
State the null and alternative hypotheses. John, a restaurant owner, suspects that prices of tomatoes in Bury are higher than the rest of Manchester. He finds that the city average price of a certain type of premium tomatoes is £20.9 with standard deviation £0.95. He takes a sample of this type of tomato from 5 local Bury stores and obtains an average price of £22.46.
Among private universities in the United States, the mean ratio of students to professors is 35.2 (i.e., 35.2 students for each professor) with a standard deviation of 8.8. Suppose a random sample of 50 universities is selected and the observed mean student-to-professor ratio is 38. Is there evidence that the reported mean ratio actually exceeds 35.2? Use  = 0.05 and conduct the appropriate hypothesis test. ( See attached picture )
A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. What is the null hypothesis for this question? Group of answer choices a. The proportion of people who pass the test is 5. b. The mean test score of the population is 5. c. The mean test score of the 50 people who took the test is 5. d.The standard deviation is 2.6
The National Weather Service says that the mean daily high temperature for October in a large mid-western city is 56°F. A local weather service suspects that this value is not accurate and wants to perform a hypothesis test to determine whether the mean is actually lower than 56°F. A sample of mean daily high temperatures for October over the past 37 years yields a sample mean of 54o F. Assume that the population standard deviation is 5.6° F. Perform the hypothesis test at the 1% significance level. STEP 1. H0: µ:____ ______o _____: H1: µ ____ o NOTE: For ≠ enter /= STEP 2. This test is (e) left-tailed, (f) two-tailed or (g) right-tailed test. This test is:___ (enter e, f or g) STEP 3. The critical value (s) is Use the following chart to identify the critical value (s) Left-tailed Two-tailed Right tailed α =10% z = -1.28 (A) z=∓1.65 (B)…
The average American consumes 89 liters of alcohol per year. Does the average college student consume less alcohol per year? A researcher surveyed 15 randomly selected college students and found that they averaged 87.3 liters of alcohol consumed per year with a standard deviation of 15 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer V Н: ? v Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the population mean is not significantly less than 89 at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean amount of alcohol consumed by college students…
A researcher wants to determine if there is a significant difference in the average math scores of two different teaching methods (Method A and Method B). He collects a sample of 50 students from each teaching method and calculates their scores. The sample mean score for Method A is 85 and the sample mean score for Method B is 80. The sample standard deviation for Method A is 4 and the sample standard deviation for Method B is 3. Conduct an independent samples t-test to determine if there is a significant difference in the average math scores of the two teaching methods at a significance level of 0.01.
(b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by √n The p-value is the area under the curve to the right of the value of the test statistic. O One-tailed o Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. Step 4: Enter the p- value. (Round to 3 decimal places.) 0.3 0.2 0.1 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the studio. o Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean player rating is higher than 90. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean player rating is higher than 90.…
Records indicate that the mean weight of mature rainbow trout in Eagle Creek is 2.25 kg with a standard deviation of 0.53 kg. After years of marked oxygen depletion from pollutants in the creek, you want to perform a hypothesis test to see if the standard deviation, σ, of weights has changed. To do so, you measure the weights of 16 randomly chosen mature rainbow trout from the creek and find that the sample standard deviation is 0.34 kg. Under the assumption that current weights of mature rainbow trout in the creek follow a normal distribution, you will perform a chi-square test.Find χ2, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places.=χ2
The mean number of eggs per person eaten in the United States is 242. Do college students eat more eggs than the average American? The 57 college students surveyed averaged 252 eggs per person and their standard deviation was 26.2. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: H₁: Select an answer Select an answer c. The test statistic ? ✓ d. The p-value = e. The p-value is ? ✓ a f. Based on this, we should g. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) Select an answer the null hypothesis. O The data suggest that the sample mean is not significantly more than 242 at a = 0.01, so there is statistically insignificant evidence to conclude that the sample mean number of eggs consumed by college students per year is more than 252. The data suggest that the populaton mean is…

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