It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the second is given by the so-called circuital law of Ampere 126 f di × (dl¡ × R) F1 = lo 4n R3 Expand the triple vector product to show that the forces satisfy Newton's 3rd law 0 = F1 + F2
It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the second is given by the so-called circuital law of Ampere 126 f di × (dl¡ × R) F1 = lo 4n R3 Expand the triple vector product to show that the forces satisfy Newton's 3rd law 0 = F1 + F2
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![It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the
second is given by the so-called circuital law of Ampere
dl x (dl, x R)
F = Ho
47
R3
Expand the triple vector product to show that the forces satisfy Newton's 3rd law
0 = F1 + F2
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65694bfc-e620-4a4d-a121-bcb6e5060fb0%2F78c775d9-9540-4957-9dd0-fa2a61b0e85d%2F3pqbz5g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the
second is given by the so-called circuital law of Ampere
dl x (dl, x R)
F = Ho
47
R3
Expand the triple vector product to show that the forces satisfy Newton's 3rd law
0 = F1 + F2
%3D
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