It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the second is given by the so-called circuital law of Ampere 126 f di × (dl¡ × R) F1 = lo 4n R3 Expand the triple vector product to show that the forces satisfy Newton's 3rd law 0 = F1 + F2

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It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the
second is given by the so-called circuital law of Ampere
dl x (dl, x R)
F = Ho
47
R3
Expand the triple vector product to show that the forces satisfy Newton's 3rd law
0 = F1 + F2
%3D
Transcribed Image Text:It has been seen that for two cables carrying currents I1 and 12. the force on the first cable due to the currents in the second is given by the so-called circuital law of Ampere dl x (dl, x R) F = Ho 47 R3 Expand the triple vector product to show that the forces satisfy Newton's 3rd law 0 = F1 + F2 %3D
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