Homework Help is Here – Start Your Trial Now!
Engineering
Civil Engineering
Isolating the right side of section a-a: By summing moments about C, force BD can be determined independently. 1200 lb B 10 BD Resolve the horizontal and vertical components of BD at B. 3. The moment of the vertical component of BD at C is zero. CD 20 V2 +U Mc = 0 3 1200(15) + (BD)(20) = 0 15' C. CE V10 BD = -948.68 lb BD= 948.68 lb (C) 400 lb Since BD turned out to be negative, the assumed sense of this force is incorrect. BD is in compression. Ay = 1200 lb By summing moments at D, force CE can be solved independently. The lines of action of force CD and BD intersect at joint D. 1200 lb B V10 3 +U EMp = -(1200 + 400)(15) + 1200(30) – CE(15) = 0 CE = 800 lb (T) CD 20" 15 C. CE Sum moments at Q to solve for CD. Resolve the horizontal and vertical components of CD at C. The moment of the horizontal Ay=1200 lb 400 lb Solve for distance x by similar triangles: component of CD at Q is zero. 20 1 x = 60 ft +U E MQ -(1200 + 400)(60) + 1200(75) + CD(60) = 0 = 0 CD = 141.42 lb (T) 105

Isolating the right side of section a-a: By summing moments about C, force BD can be determined independently. 1200 lb B 10 BD Resolve the horizontal and vertical components of BD at B. 3. The moment of the vertical component of BD at C is zero. CD 20 V2 +U Mc = 0 3 1200(15) + (BD)(20) = 0 15' C. CE V10 BD = -948.68 lb BD= 948.68 lb (C) 400 lb Since BD turned out to be negative, the assumed sense of this force is incorrect. BD is in compression. Ay = 1200 lb By summing moments at D, force CE can be solved independently. The lines of action of force CD and BD intersect at joint D. 1200 lb B V10 3 +U EMp = -(1200 + 400)(15) + 1200(30) – CE(15) = 0 CE = 800 lb (T) CD 20" 15 C. CE Sum moments at Q to solve for CD. Resolve the horizontal and vertical components of CD at C. The moment of the horizontal Ay=1200 lb 400 lb Solve for distance x by similar triangles: component of CD at Q is zero. 20 1 x = 60 ft +U E MQ -(1200 + 400)(60) + 1200(75) + CD(60) = 0 = 0 CD = 141.42 lb (T) 105

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
See similar textbooks
icon
Related questions
Question

Can I have some clarification on why the components of the moment of BD became (20)(3)/(10)^1/2 and similarly with CD became (1)(60)/(2)^1/2.? Thank you

Section d-a CUIS The bars BD, CD, and CE. The leti side or ight side Or section d-a can be isolated as the FBD. Assume tension for the forces BD, CD, and CE. Isolating the right side of section a-a: By summing moments about C, force BD can be determined independently. 1200 lb 10 BD Resolve the horizontal and vertical components of BD at B. The moment of the vertical component of BD at C is zero. 3 CD 20 V2 +U £Mc = 0 %3D 3 1200(15) + (BD)(20) = 0 10 %3D 15' CE BD = –948.68 lb BD= 948.68 lb (C) 400 lb Since BD turned out to be negative, the assumed sense of this force is incorrect. BD is in compression. Ay = 1200 lb By summing moments at D, force CE can be solved independently. The lines of action of force CD and BD intersect at joint D. 1200 lb 10 BD D. +U £ Mp = 0 -(1200 + 400)(15)+ 1200(30) – CE(15) = 0 CE = 800 lb (T) CD %3D 20' Q 15' CE Sum moments at Q to solve for CD. Resolve the horizontal and vertical components of CD at C. The moment of the horizontal X. Av=1200 lb 400 lb Solve for distance x by similar triangles: component of CD at Q is zero. 3 20 1 +U £Mo = 0 %3D X- 60 ft %3D -(1200 + 400)(60) + 1200(75) +CD(60) = 0 CD = 141.42 lb (T) %3D 105 C.
Transcribed Image Text:Section d-a CUIS The bars BD, CD, and CE. The leti side or ight side Or section d-a can be isolated as the FBD. Assume tension for the forces BD, CD, and CE. Isolating the right side of section a-a: By summing moments about C, force BD can be determined independently. 1200 lb 10 BD Resolve the horizontal and vertical components of BD at B. The moment of the vertical component of BD at C is zero. 3 CD 20 V2 +U £Mc = 0 %3D 3 1200(15) + (BD)(20) = 0 10 %3D 15' CE BD = –948.68 lb BD= 948.68 lb (C) 400 lb Since BD turned out to be negative, the assumed sense of this force is incorrect. BD is in compression. Ay = 1200 lb By summing moments at D, force CE can be solved independently. The lines of action of force CD and BD intersect at joint D. 1200 lb 10 BD D. +U £ Mp = 0 -(1200 + 400)(15)+ 1200(30) – CE(15) = 0 CE = 800 lb (T) CD %3D 20' Q 15' CE Sum moments at Q to solve for CD. Resolve the horizontal and vertical components of CD at C. The moment of the horizontal X. Av=1200 lb 400 lb Solve for distance x by similar triangles: component of CD at Q is zero. 3 20 1 +U £Mo = 0 %3D X- 60 ft %3D -(1200 + 400)(60) + 1200(75) +CD(60) = 0 CD = 141.42 lb (T) %3D 105 C.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Structural Analysis
Structural Analysis
Civil Engineering
ISBN:
9781337630931
Author:
KASSIMALI, Aslam.
Publisher:
Cengage,
Structural Analysis (10th Edition)
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Fundamentals of Structural Analysis
Fundamentals of Structural Analysis
Civil Engineering
ISBN:
9780073398006
Author:
Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:
McGraw-Hill Education
Sustainable Energy
Sustainable Energy
Civil Engineering
ISBN:
9781337551663
Author:
DUNLAP, Richard A.
Publisher:
Cengage,
Traffic and Highway Engineering
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS