Is the following indentity true? sec (6)-tan (0) = 1+sin? (e) cos?(0)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Is the following indentity true?
![### Trigonometric Identity Verification
Consider the following identity:
\[ \sec^4(\theta) - \tan^4(\theta) = \frac{1 + \sin^2(\theta)}{\cos^2(\theta)} \]
**Objective:** Determine if this identity is true.
**Explanation:**
1. **Left Hand Side (LHS):**
- \(\sec(\theta) = \frac{1}{\cos(\theta)}\)
- \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\)
- Therefore, \(\sec^4(\theta) = \left(\frac{1}{\cos(\theta)}\right)^4 = \frac{1}{\cos^4(\theta)}\)
- And \(\tan^4(\theta) = \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^4 = \frac{\sin^4(\theta)}{\cos^4(\theta)}\)
- Thus, LHS becomes:
\[ \frac{1}{\cos^4(\theta)} - \frac{\sin^4(\theta)}{\cos^4(\theta)} = \frac{1 - \sin^4(\theta)}{\cos^4(\theta)} \]
2. **Right Hand Side (RHS):**
- \(\frac{1 + \sin^2(\theta)}{\cos^2(\theta)}\)
**Conclusion:**
The identity reduces to comparing:
\[ \frac{1 - \sin^4(\theta)}{\cos^4(\theta)} \quad \text{and} \quad \frac{1 + \sin^2(\theta)}{\cos^2(\theta)} \]
To determine if they are indeed equal, further simplification or manipulation might be required.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe069bb76-d12a-4659-9fff-a2d2132df1d6%2F8277741a-471b-4e1b-9f77-20337c150fb6%2Fymmyv4k_processed.png&w=3840&q=75)
Transcribed Image Text:### Trigonometric Identity Verification
Consider the following identity:
\[ \sec^4(\theta) - \tan^4(\theta) = \frac{1 + \sin^2(\theta)}{\cos^2(\theta)} \]
**Objective:** Determine if this identity is true.
**Explanation:**
1. **Left Hand Side (LHS):**
- \(\sec(\theta) = \frac{1}{\cos(\theta)}\)
- \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\)
- Therefore, \(\sec^4(\theta) = \left(\frac{1}{\cos(\theta)}\right)^4 = \frac{1}{\cos^4(\theta)}\)
- And \(\tan^4(\theta) = \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^4 = \frac{\sin^4(\theta)}{\cos^4(\theta)}\)
- Thus, LHS becomes:
\[ \frac{1}{\cos^4(\theta)} - \frac{\sin^4(\theta)}{\cos^4(\theta)} = \frac{1 - \sin^4(\theta)}{\cos^4(\theta)} \]
2. **Right Hand Side (RHS):**
- \(\frac{1 + \sin^2(\theta)}{\cos^2(\theta)}\)
**Conclusion:**
The identity reduces to comparing:
\[ \frac{1 - \sin^4(\theta)}{\cos^4(\theta)} \quad \text{and} \quad \frac{1 + \sin^2(\theta)}{\cos^2(\theta)} \]
To determine if they are indeed equal, further simplification or manipulation might be required.
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