Based on a sample of 80 textbooks at the store, you find an average of 64.66 and a standard deviation of 17. The point estimate is: (to 3 decimals) The 90 % confidence interval (use z*) is: to (to 3 decimals)
Based on a sample of 80 textbooks at the store, you find an average of 64.66 and a standard deviation of 17. The point estimate is: (to 3 decimals) The 90 % confidence interval (use z*) is: to (to 3 decimals)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC
bookstore costs $ 52.86. You want to test this claim.
The null and alternative hypothesis in symbols would be:
O Ho:p < 52.86
H:p> 52.86
o Ho:p < 52.86
H:p> 52.86
O Ho:p 2 52.86
H:p < 52.86
O Ho p 52.86
H:p 52.86
O Ho:p > 52.86
H:p < 52.86
o Ho: u 52.86
H:p+52.86
The null hypothesis in words would be:
The average price of textbooks in a sample is 5 52.86
O The average of price of all textbooks from the store is less than $ 52.86.
O The average price of all textbooks from the store is $ 52.86
The average of price of all textbooks from the store is greater than $ 52.86,
The proportion of all textbooks from the store that are less than 52.86 is equal to 50%
of
Based on a sample of 80 textbooks at the store, you find an average of 64.66 and a standard deviation of
17.
The point estimate is:
(to 3 decimals)
The 90 % confidence interval (use z*) is:
to
(to 3 decimals)
of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F204a4cc4-311e-434b-b228-6b425ea7385e%2Fe1441c98-8958-49b2-9682-02f150f821c2%2Fvectbla_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC
bookstore costs $ 52.86. You want to test this claim.
The null and alternative hypothesis in symbols would be:
O Ho:p < 52.86
H:p> 52.86
o Ho:p < 52.86
H:p> 52.86
O Ho:p 2 52.86
H:p < 52.86
O Ho p 52.86
H:p 52.86
O Ho:p > 52.86
H:p < 52.86
o Ho: u 52.86
H:p+52.86
The null hypothesis in words would be:
The average price of textbooks in a sample is 5 52.86
O The average of price of all textbooks from the store is less than $ 52.86.
O The average price of all textbooks from the store is $ 52.86
The average of price of all textbooks from the store is greater than $ 52.86,
The proportion of all textbooks from the store that are less than 52.86 is equal to 50%
of
Based on a sample of 80 textbooks at the store, you find an average of 64.66 and a standard deviation of
17.
The point estimate is:
(to 3 decimals)
The 90 % confidence interval (use z*) is:
to
(to 3 decimals)
of
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