is positive in this this in Си reaction explain why 2ncl2n^² || Cut ³ | Cu 2 8170 € 9969

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## Electrolytic Cell Question

**Question 3:**

*Explain the transformation when an electrolytic cell is in operation. Discuss why Cu is positive in this reaction:*

\[ \text{Zn(s) | Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \]

---

### Explanation:

An electrolytic cell is a device that uses electrical energy to drive a non-spontaneous chemical reaction. When an electrolytic cell is in operation, the external electrical energy forces electrons to move towards the cathode and away from the anode, causing oxidation-reduction reactions to occur.

In this specific reaction:

\[ \text{Zn(s) | Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \]

- **Anode Reaction (Oxidation):** Zinc (Zn) loses electrons to form zinc ions \( \text{Zn}^{2+} \):
  \[
  \text{Zn} \rightarrow \text{Zn}^{2+} + 2\text{e}^-
  \]

- **Cathode Reaction (Reduction):** Copper ions \( \text{Cu}^{2+} \) gain electrons to form copper (Cu):
  \[
  \text{Cu}^{2+} + 2\text{e}^- \rightarrow \text{Cu}
  \]

In an electrolytic cell, the anode is the positive electrode, and the cathode is the negative electrode. However, the specifics provided in the question suggest a galvanic cell notation where zinc is initially oxidized and copper is reduced.

### Why Cu is Positive

Copper (Cu) is referenced as positive in this reaction because it is involved in the reduction half-reaction, gaining electrons. In the traditional sense of an electrolytic cell setup:
- The **anode** (where oxidation occurs) is positively charged.
- The **cathode** (where reduction occurs) is negatively charged.

However, based on the cell notation provided (which typically represents a galvanic cell structure), Zn is the anode that gets oxidized, and Cu is the cathode that gets reduced. Hence, the question might imply that copper ions (Cu²⁺) are initially present on the positive side of the galvanic cell setup, showing they get reduced during the operation.

### Conclusion

Understanding the transformation in an electrolytic setup requires knowing the specific reactions and
Transcribed Image Text:## Electrolytic Cell Question **Question 3:** *Explain the transformation when an electrolytic cell is in operation. Discuss why Cu is positive in this reaction:* \[ \text{Zn(s) | Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \] --- ### Explanation: An electrolytic cell is a device that uses electrical energy to drive a non-spontaneous chemical reaction. When an electrolytic cell is in operation, the external electrical energy forces electrons to move towards the cathode and away from the anode, causing oxidation-reduction reactions to occur. In this specific reaction: \[ \text{Zn(s) | Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \] - **Anode Reaction (Oxidation):** Zinc (Zn) loses electrons to form zinc ions \( \text{Zn}^{2+} \): \[ \text{Zn} \rightarrow \text{Zn}^{2+} + 2\text{e}^- \] - **Cathode Reaction (Reduction):** Copper ions \( \text{Cu}^{2+} \) gain electrons to form copper (Cu): \[ \text{Cu}^{2+} + 2\text{e}^- \rightarrow \text{Cu} \] In an electrolytic cell, the anode is the positive electrode, and the cathode is the negative electrode. However, the specifics provided in the question suggest a galvanic cell notation where zinc is initially oxidized and copper is reduced. ### Why Cu is Positive Copper (Cu) is referenced as positive in this reaction because it is involved in the reduction half-reaction, gaining electrons. In the traditional sense of an electrolytic cell setup: - The **anode** (where oxidation occurs) is positively charged. - The **cathode** (where reduction occurs) is negatively charged. However, based on the cell notation provided (which typically represents a galvanic cell structure), Zn is the anode that gets oxidized, and Cu is the cathode that gets reduced. Hence, the question might imply that copper ions (Cu²⁺) are initially present on the positive side of the galvanic cell setup, showing they get reduced during the operation. ### Conclusion Understanding the transformation in an electrolytic setup requires knowing the specific reactions and
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