To gauge their fear of going to a dentist, a random sample of adults completed the Modified Dental Anxiety Scale questionnaire (BMC Oral Health, Vol. 9, 2009). Scores on the scale range from zero (no anxiety) to 25 (extreme anxiety). The mean score was 11 and the standard deviation was 4. Assume that the distribution of all scores on the Modified Dental Anxiety Scale is approximately normal with μ = 11 and σ = 4. Complete parts a through c below.a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for this score.z = ☐ (Round to two decimal places as needed.)

Is approkimat and 6=4. Complete parts a through c below. ...... a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for this score. (Round to two decimal places as needed.)

Is approkimat and 6=4. Complete parts a through c below. ...... a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for this score. (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Expert Solution

Step 1

Let X be a random variable following normal distribution with mean $μ$ and variance $σ^{2}$ , i.e., $X ~ N (μ, σ^{2})$ . The standard normal variate define for X is given as:

$Z = \frac{X - μ}{σ} ~ N (0, 1)$

Total area underneath a standard normal curve is equal to 1. When a Z-score is below (-2) or above 2 then, that Z-score is considered as a extreme value.

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