Is a statistics class' delivery type a factor in how well students do on the final exam? The table below shows the average percent on final exams from several randomly selected classes that used the different delivery types. Face-to-Face Hybrid | Online 76 99 72 65 59 96 63 71 66 82 99 99 65 73 100 65 100 85 64 94 76 75 57 Assume that all distributions are normal, the three population standard deviations are all the same, the data was collected independently and randomly. Use a level of significance of = 0.1. and Ho: µi = µ2 = µ3 H1: At least two of the means differ from each other.
Is a statistics class' delivery type a factor in how well students do on the final exam? The table below shows the average percent on final exams from several randomly selected classes that used the different delivery types. Face-to-Face Hybrid | Online 76 99 72 65 59 96 63 71 66 82 99 99 65 73 100 65 100 85 64 94 76 75 57 Assume that all distributions are normal, the three population standard deviations are all the same, the data was collected independently and randomly. Use a level of significance of = 0.1. and Ho: µi = µ2 = µ3 H1: At least two of the means differ from each other.
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Question
![Is a statistics class' delivery type a factor in how well
students do on the final exam? The table below
shows the average percent on final exams from
several randomly selected classes that used the
different delivery types.
Face-to-Face
Нybrid
Online
76
99
72
65
59
96
63
71
66
82
99
99
65
73
100
65
100
85
64
94
76
75
57
Assume that all distributions are normal, the three
population standard deviations are all the same, and
the data was collected independently and randomly.
Use a level of significance of a =
= 0.1.
Ho: µ1 = l2 = µ3
H1: At least two of the means differ from each
other.
1. For this study, we should use
ANOVA
2. The test-statistic for this data =
1.650
(Please show your answer to 3 decimal
places.)
3. The p-value for this sample :
0.2113 X
(Please show your answer to 4 decimal
places.)
4. The p-value is ( less than (or equal to) alpha
5. Base on this, we should
reject the null hypothesis
hypothesis
6. As such, the final conclusion is that...
O There is sufficient evidence to support
the claim that course delivery type is a
factor in final exam score.
| There is insufficient evidence to
support the claim that course delivery
type is a factor in final exam score.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ee6c1af-adde-424f-bb4c-5af98601ff50%2F65d9a79c-d4da-4d51-86de-b7ad8fa9327f%2Fela6vda_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Is a statistics class' delivery type a factor in how well
students do on the final exam? The table below
shows the average percent on final exams from
several randomly selected classes that used the
different delivery types.
Face-to-Face
Нybrid
Online
76
99
72
65
59
96
63
71
66
82
99
99
65
73
100
65
100
85
64
94
76
75
57
Assume that all distributions are normal, the three
population standard deviations are all the same, and
the data was collected independently and randomly.
Use a level of significance of a =
= 0.1.
Ho: µ1 = l2 = µ3
H1: At least two of the means differ from each
other.
1. For this study, we should use
ANOVA
2. The test-statistic for this data =
1.650
(Please show your answer to 3 decimal
places.)
3. The p-value for this sample :
0.2113 X
(Please show your answer to 4 decimal
places.)
4. The p-value is ( less than (or equal to) alpha
5. Base on this, we should
reject the null hypothesis
hypothesis
6. As such, the final conclusion is that...
O There is sufficient evidence to support
the claim that course delivery type is a
factor in final exam score.
| There is insufficient evidence to
support the claim that course delivery
type is a factor in final exam score.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
1.
Since the means of more than two groups have to be compared ANOVA has to be used. Thus, ANOVA should be used for this study.
2.
The ANOVA is conducted by using EXCEL. The software procedure is given below:
- Enter the data.
- Select Data > Data Analysis >ANOVA: Single Factor> OK.
- Enter Input Range as A1:C9.
- Mark Labels in First Row.
- Enter Alpha as 0.10.
- Click OK.
The output using EXCEL is as follows:
From the output, the test statistic value is 2.606.
Thus, the test statistic is 2.606.
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