Is (8,2) inside, outside, or on the circle (x- 5)? +y = 16? Explain. The distance between (8,2) and (5,0) is the radius of the circle, 4. So, the point (8,2) is the circle (x - 5)2 +y = 16.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Is (8,2) inside, outside, or on the circle (x- 5) +y = 16? Explain.
The distance between (8,2) and (5,0) is
the radius of the circle, 4. So, the point (8,2) is
the circle (x - 5)? +y² = 16.
Transcribed Image Text:Is (8,2) inside, outside, or on the circle (x- 5) +y = 16? Explain. The distance between (8,2) and (5,0) is the radius of the circle, 4. So, the point (8,2) is the circle (x - 5)? +y² = 16.
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