IQ scores are normally distributed with an average of 100 and a standard deviation of 16. Some research suggests that left-handed individuals have a higher IQ score than right-handed individuals. To test this hypothesis, you randomly select 132 individuals and find that their average IQ is 103.2 with a sample standard deviation of 14.6. You formulate the null hypothesis H0: μ = H> versus the alternative hypothesis H1: Using the results from the sample, you calculate the test statistic as t = ( )/( N Hint: Write the t-statistic (value in the last blank) in two decimal places. Since the critical value for the one-sided alternative is level, you reject the null hypothesis. Hint: Write the critical value in two decimal places. ) = at the 5% significance

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IQ scores are normally distributed with an average of 100 and a standard deviation of 16.
Some research suggests that left-handed individuals have a higher IQ score than right-handed
individuals.
To test this hypothesis, you randomly select 132 individuals and find that their average IQ is 103.2 with a
sample standard deviation of 14.6.
You formulate the null hypothesis H0: µ =
H>
versus the alternative hypothesis H1:
Using the results from the sample, you calculate the test statistic as t = (
)/(
N
) =
Hint: Write the t-statistic (value in the last blank) in two decimal places.
Since the critical value for the one-sided alternative is
level, you reject the null hypothesis. Hint: Write the critical value in two decimal places.
at the 5% significance
Transcribed Image Text:IQ scores are normally distributed with an average of 100 and a standard deviation of 16. Some research suggests that left-handed individuals have a higher IQ score than right-handed individuals. To test this hypothesis, you randomly select 132 individuals and find that their average IQ is 103.2 with a sample standard deviation of 14.6. You formulate the null hypothesis H0: µ = H> versus the alternative hypothesis H1: Using the results from the sample, you calculate the test statistic as t = ( )/( N ) = Hint: Write the t-statistic (value in the last blank) in two decimal places. Since the critical value for the one-sided alternative is level, you reject the null hypothesis. Hint: Write the critical value in two decimal places. at the 5% significance
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