ipa = e- V2Th 8 (x – x') Suppose(p | ) = e¯. What is (x | v) =? *. What is (x | p) =? O 2nħ 8 (x – x') 1 - 2Th 8 (x – x')
ipa = e- V2Th 8 (x – x') Suppose(p | ) = e¯. What is (x | v) =? *. What is (x | p) =? O 2nħ 8 (x – x') 1 - 2Th 8 (x – x')
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Transcribed Image Text:Suppose \(\langle p \mid \psi \rangle = e^{-\frac{ipx}{\hbar}}\). What is \(\langle x \mid \psi \rangle = ?\)
Options:
1. \( \sqrt{2\pi \hbar} \, \delta(x - x') \)
2. \( 2\pi \hbar \)
3. \( \frac{1}{\sqrt{2\pi \hbar}} \, \delta(x - x') \)
4. \( \delta(x - x') \)
Each option proposes a possible expression for the wave function \(\langle x \mid \psi \rangle\) given the initial condition. Here, \(\delta(x - x')\) represents the Dirac delta function, which is used to describe a discrete point in space.
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