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Ip=12 A Re www 13 Ω + aVL For the transformer equivalent circuit shown what is the source voltage (Vg = ?) a. 3096 +j156 V b. 3036 + 1216 V c. No right answer d. 876 +j156 V X₂ moo 18 Ω a²R₁ = (4)(602) = 240 Ω

Ip=12 A Re www 13 Ω + aVL For the transformer equivalent circuit shown what is the source voltage (Vg = ?) a. 3096 +j156 V b. 3036 + 1216 V c. No right answer d. 876 +j156 V X₂ moo 18 Ω a²R₁ = (4)(602) = 240 Ω

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Ip = 12 A Re ww 13 Ω + aVL a²R₁ For the transformer equivalent circuit shown what is the source voltage (Vg = ?) a. 3096 +j156 V b. 3036 + 1216 V c. No right answer d. 876 +j156 V Xe moo 18 Ω = (4)(60 Ω) = 240 Ω Ω
Transcribed Image Text:Ip = 12 A Re ww 13 Ω + aVL a²R₁ For the transformer equivalent circuit shown what is the source voltage (Vg = ?) a. 3096 +j156 V b. 3036 + 1216 V c. No right answer d. 876 +j156 V Xe moo 18 Ω = (4)(60 Ω) = 240 Ω Ω
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