ions 14-15; Convert the following LP primal problem into dual problem.Max P =-3x1 +3x2+2x3-2x4-x5+4x6Subject To:xl x2 + x3 x4-4x5+2x6-x7 ≤4,3xl-3x2-x3+ x4 + 2x52-6,-x3 + x4+x6 ≤ 1x1-x2 + x3 x4 x5 ≤0x1,x2,x3,x4,x5,x6,x720The Objective Function is:

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Answered: ions 14-15; Convert the following LP…

Advanced Engineering Mathematics

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ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

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5. The nonlinear system xỉ – 10x1 + x, = -8, x1x3+ x1 – 10x2 + 8 = 0 can be transformed into the fixed-point problem xž + x3 + 8 x1x3 + x1 + 8 X1 = 91(x1, x2) x2 = 92(x1, x2) 10 10 (a) Show that G (91, 92)* mapping D into R? has a unique fixed point in D = {X = (x1, 82)' : 0 < x; < 1.5, i = 1, 2}. (b) Apply functional iteration to approximate the solution.
2 Minimize subject tos X+2x2 +3x3-12 0 X2+ 2x3+3x4- 4 0 by direct substitation method.
Q2. Use cutting plane method to solve the integer programming problem Maximize 2x, + 3x2 -x1 +x25 5, X1 +3x2 < 35, X1 +x2 S 20, X1, X2 are non-negative integers. Subject to
1. Use the simplex method in tabular form to solve the problem: Maximize Z= 2x1 + 4x2 + 3x3 subject to and 21 +372 +2r3 ≤ 30 21+22+13 ≤ 24 3x1 +52 + 3x3 ≤60 2120, 220, 23 20.
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A suitable form of the general solution to the y-4y=x by the undetermined coefficient method is ,ge +c,xe + Ax e + Bx +C +c,x* + Axe + Bxr+C I. Gxe +c,e + Ax + Bx + C IV. Gxe +c,e + Ax +B V. Ge +ce+Ax + Bx Select one: O a. II O b. II Activate Windows Go to Settings to activate Windows. O c. V O d. IV O e. I 2:49 PM 1/22/2021 AK bęko
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2. Minimize z - 6х, + 6х, + 8x, + 9х, subject to X, + 2xz + x3+ X4 2 3 2x, + xz + 4x3 + 9x42 8 X, 2 0, x2 2 0, x3 2 0, x,2 0.
:How finite difference and collocation methods are useful to solve BVPs. Also discuss stability of each method .
4- Write just the first table of Big-M method for the following problem Max Z = 2X1 + X2 s.t. -3X1 + X222 2X1 X₂ ≤3 - 5X1 - 2X2 = 1 X₁ ≥ 0, X₂ ≥0
Question 29 Maximize 2x1 + 4x2 subject to x1 + 3x₂ �� 12 2x1 + x₂ ≤ 14 120 and ₂ > 0 Using simplex method by introducing slack variables 3 and 4, and M = 2x1 + 4x2, now the inequalities are changed to equations x1 + 3x2 + x3 = 12 (1) 2x1 + x₂ + x4 = 14 (2) 2x14x2 M = 0 (3) To bring 1 and 2 into the solution, which one (1 or 2) is firstly brought into the solution and which equation is used as the pivot equation. O1 and (2) O #2 and (3) O2 and (2) O #1 and (1) O2 and (1)
Мах Z 3D 4x, + 3xz st. 2x1 < 12 (1) 2 x2 < 24 (2) Зх, + 2х, < к (3) X1 (4) x2 2 0 (5) Given the following the LP. Write a relevant integer value for K such that the problem remains feasible and the constraint (3) becomes redundant. A relevant value for K =

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ions 14-15; Convert the following LP primal problem into dual problem. Max P =-3x1 +3x2+2x3-2x4-x5+4x6 Subject To: xl-x2 + x3 x4-4x5+2x6-x7 ≤4, 3x13x2-x3 + x4 + 2x52-6, -x3 + x4+x6 ≤ 1 x1-x2 + x3 x4 x5 ≤0 x1,x2,x3,x4,x5,x6,x720 The Objective Function is: