Ionizing radiation enters a Geiger tube with 1.30 MeV of energy. As the radiation passes through the tube, all of this energy goes into creating ion pairs and each ion pair requires 30 eV of energy. (a) If an applied voltage sweeps these ions out of the gas in 1.10 µs, determine the current (in A).   (b)Since the applied voltage in the Geiger tube accelerates these separated ions, creating other ion pairs in subsequent collisions, the actual current is greater than that determined in part (a). If this effect multiplies the number of ion pairs by 920, determine the actual current (in A).

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Chapter1: Units, Trigonometry. And Vectors
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Ionizing radiation enters a Geiger tube with 1.30 MeV of energy. As the radiation passes through the tube, all of this energy goes into creating ion pairs and each ion pair requires 30 eV of energy.

(a) If an applied voltage sweeps these ions out of the gas in 1.10 µs, determine the current (in A).
 
(b)Since the applied voltage in the Geiger tube accelerates these separated ions, creating other ion pairs in subsequent collisions, the actual current is greater than that determined in part (a). If this effect multiplies the number of ion pairs by 920, determine the actual current (in A).
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