Rapid Eye Movement (REM) sleep is the sleep when a person has dreams. A researcher wants toinvestigate whether children have more REM than adults. She selects a random sample of 10 children andobtained a mean of 2.9 hours and standard deviation of 0.48 hours for the duration of REM sleep. She alsoselected a random sample of 10 adults and the mean and standard deviation of the duration of their REM sleep8.were 2.1 hours and 0.68 hours.A.than the average REM for adults? Use the p-value method.At a = 0.05, is there enough evidence to conclude that the average REM for children is higherВ.Find the 95% confidence interval for the difference between the average REM for children andthe average REM for adults. Interpret your results.

Given Data : For Sample 1 x̄1 = 2.9 s1 = 0.48 n1 = 10 For Sample 2…

Answered: investigate whether children have more…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A student researcher compares the heights of American students and non-American students from the student body of a certain college in order to estimate the difference in their mean heights. A random sample of 1212 American students had a mean height of 68.468.4 inches with a standard deviation of 2.462.46 inches. A random sample of 1717 non-American students had a mean height of 65.165.1 inches with a standard deviation of 2.962.96 inches. Determine the 98%98% confidence interval for the true mean difference between the mean height of the American students and the mean height of the non-American students. Assume that the population variances are equal and that the two populations are normally distributed. Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
A researcher knew that before cell phones, a person made on average 3.2 calls per day. He believes that the number of calls made per day today is higher. He selects a random sample of 28 individuals who use a cell phone and asks them to keep track of the number of calls that they made on a certain day. The mean was 3.5. At (alpha) = 0.01, is there enough evidence to support the researchers claim? The standard deviation for the population found by a previous study is 0.9. Assume that the variable is normally distributed. Use the critical value method with tables. A. State the hypotheses and identify the claim with the correct hypothesis. B. Find the critical value(s). C. Compute the test value. D. Make the decision. E. Summarize the results.
A psychologist is studying smokers' self-images, which she measures by the self-image (SI) score from a personality inventory. For adults in the U.S., the mean SI score from this inventory is about 150.The psychologist gathers a random sample of 15 SI scores of smokers and finds that their mean is 126 and their standard deviation is 37. Assume that the population of SI scores of smokers is normally distributed with mean μ. Based on the sample, can the psychologist conclude that μ is different from 150? Use the 0.05 level of significance. Perform a two-tailed test. Then fill in the table below.Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. The null hypothesis: H0: The alternative hypothesis: H1: The type of test statistic: (Choose one) Z t Chisquare F The value of the test statistic:(Round to at least three decimal places.) The p-value:(Round to at least…
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The water consumption per week by Brampton residences is normally distributed with an average of 125 gallons of water and a standard deviation of 10 gallons. The city of Brampton claims that the average water consumed in the state of Brampton is not 125 gallons. A team of AU students draws a simple random sample of 10 residences and find the mean consumption value of 120.3 gallons. Calculate the Zc and p-value showing all the steps.
A random sample of 10 subjects have weights with a standard deviation of 11.9848 kg . What is the variance of their weights ? Be sure to include the appropriate units with the result .
An Internet provider has analyzed the amount of time it’s customers are online per session. It found that the distribution of connect times has a mean a 43 minutes and a standard deviation of 10 minutes. For this distribution find the raw score that corresponds to a z score of 1.1
A recent study stated that if a person chewed gum, the average number of sticks of gum he or she chewed daily was 8. To test the claim, the researcher selected a random sample of 36 gum chewers and found the mean number of sticks of gum chewed per day was 8. The standard deviation of population is 1. at a = 0. 05, is the number of sticks of gum a person chews per day actually greater than 8. There is not enough evidence to support the claim that average is greater than 8. There is enough evidence to support the claim that average is greater than 8. There is enough evidence to support the claim that average is smaller than 8. There is not enough evidence to support the claim that average is greater than 8.
A study showed that two years ago, the mean time spent per visit to Facebook was 20.1 minutes. Assume the standard deviation is 7 minutes. Suppose that a simple random sample of 103 visits was selected this year and has a sample mean of 22.1 minutes. A social scientist is interested to know whether the mean time of Facebook visits has changed. Use the a=0.05 level of significance and the p-value method with the table.
A psychologist is studying smokers' self-images, which she measures by the self-image (SI) score from a personality inventory. For adults in the U.S., the mean SI score from this inventory is about 150. The psychologist gathers a random sample of 16 SI scores of smokers and finds that their mean is 130 and their standard deviation is 31. Assume that the population of SI scores of smokers is normally distributed with mean μ. Based on the sample, can the psychologist conclude that μ is different from 150? Use the 0.05 level of significance. Perform a two-tailed test. Then fill in the table attached. Carry your intermediate computations to at least three decimal places and round your answers as specified in the table.

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