Internet. How is the PC able to keep track of the data flow between multiple application sessions and have 16-A technician with a PC is using multiple applications each application receive the correct packet flows? a) The data flow is being tracked based on the source port number that is used by each application. b) The data flow is being tracked based on the destination IP address that is used by the PC of the technician. c) The data flow is being tracked based on the source IP address that is used by the PC of the technician. d) The data flow is being tracked based on the destination MAC address of the technician PC. 17- Refer to the exhibit. Match the network with the correct IP address and prefix that will atisfy the usable host addressing requirements for each network. (Not all options are used.) Network C 2 2 2 2 2 2 4 Network B 50 Hosts (4-3/26 Network D 2 Hosts Network A A) Network B-192.168.0.0/25 A-192.168.0.128/26 C 192.168.0.192/27 D-192.168.0.224/30 ) Network A-192.168.0.0/25 B-192.168.0.128/26 C 192.168.0.192/27 D-192.168.0.224/30 Network A-192.168.0.0/25 B-192.168.0.128/26 D-192.168.0.192/27 C-192.168.0.224/30 Network D-192.168.0.0/25 B-192.168.0.128/26 C-192.168.0.192/27 A-192.168.0.224/30 Network A-192.168.0.0/25 D-192.168.0.128/26 C-192.168.0.192/27 B-192.168.0.224/30
Internet. How is the PC able to keep track of the data flow between multiple application sessions and have 16-A technician with a PC is using multiple applications each application receive the correct packet flows? a) The data flow is being tracked based on the source port number that is used by each application. b) The data flow is being tracked based on the destination IP address that is used by the PC of the technician. c) The data flow is being tracked based on the source IP address that is used by the PC of the technician. d) The data flow is being tracked based on the destination MAC address of the technician PC. 17- Refer to the exhibit. Match the network with the correct IP address and prefix that will atisfy the usable host addressing requirements for each network. (Not all options are used.) Network C 2 2 2 2 2 2 4 Network B 50 Hosts (4-3/26 Network D 2 Hosts Network A A) Network B-192.168.0.0/25 A-192.168.0.128/26 C 192.168.0.192/27 D-192.168.0.224/30 ) Network A-192.168.0.0/25 B-192.168.0.128/26 C 192.168.0.192/27 D-192.168.0.224/30 Network A-192.168.0.0/25 B-192.168.0.128/26 D-192.168.0.192/27 C-192.168.0.224/30 Network D-192.168.0.0/25 B-192.168.0.128/26 C-192.168.0.192/27 A-192.168.0.224/30 Network A-192.168.0.0/25 D-192.168.0.128/26 C-192.168.0.192/27 B-192.168.0.224/30
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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i need clear ans and solve very very fast in 20 min and thank you | ᴅʏʙᴀʟᴀ ?✨؛
Transcribed Image Text:a)DNS b) HTTP c) DHCP
d) SMTP
16-A technician with a PC is using multiple applications while connected to the Internet. How
is the PC able to keep track of the data flow between multiple application sessions and have
each application receive the correct packet flows?
a) The data flow is being tracked based on the source port number that is used by each
application.
b) The data flow is being tracked based on the destination IP address that is used by the PC
of the technician.
c) The data flow is being tracked based on the source IP address that is used by the PC of
the technician.
d) The data flow is being tracked based on the destination MAC address of the technician
PC.
17- Refer to the exhibit. Match the network with the correct IP address and prefix that will
satisfy the usable host addressing requirements for each network. (Not all options are used.)
2 2 2 2 2 2 4
Network C
25 Hosts
Network B
50 Hosts
(4=2/26
Network D
2 Hosts
Network A
100 Ho
A) Network B-192.168.0.0/25 A-192.168.0.128/26 C=192.168.0.192/27 D-192.168.0.224/30
B) Network A-192.168.0.0/25 B-192.168.0.128/26 C=192.168.0.192/27 D-192.168.0.224/30
C) Network A-192.168.0.0/25 B-192.168.0.128/26 D=192.168.0.192/27 C-192.168.0.224/30
D) Network D-192.168.0.0/25 B-192.168.0.128/26 C192.168.0.192/27 A-192.168.0.224/30
E) Network A-192.168.0.0/25 D-192.168.0.128/26 C-192.168.0.192/27 B-192.168.0.224/30
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