Internet Visits A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits a particular website per user from home. A random sample of 31 Internet users yielded a sample mean of 38.1 visits with a standard deviation of 5.3. At the 0.02 level of significance can it be concluded that this differs from the national average? Assume the population is normally distributed. Usa a TI-83 Plus TI-84 Plus calculaton #2(8.3) the hypotheses and identify the claim. <=36 not claim 36 caim pothesis cast is a two-tailed test Pvalue=
Internet Visits A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits a particular website per user from home. A random sample of 31 Internet users yielded a sample mean of 38.1 visits with a standard deviation of 5.3. At the 0.02 level of significance can it be concluded that this differs from the national average? Assume the population is normally distributed. Usa a TI-83 Plus TI-84 Plus calculaton #2(8.3) the hypotheses and identify the claim. <=36 not claim 36 caim pothesis cast is a two-tailed test Pvalue=
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please round 4 dec places , find value .
Reject null hypothesis or not?
Do you have evidence?
![**Internet Visits Analysis**
A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits to a particular website per user from home. A random sample of 31 Internet users yielded a sample mean of 38.1 visits with a standard deviation of 5.3. At the 0.02 level of significance, can it be concluded that this differs from the national average? Assume the population is normally distributed. Use a TI-83 Plus/TI-84 Plus calculator for the calculation.
### Hypothesis Test
1. **State the Hypotheses:**
- \( H_0: \mu = 36 \) (not claim)
- \( H_1: \mu \neq 36 \) (claim)
2. **Type of Test:**
- A two-tailed test
3. **P-value:**
- To be calculated
**Note:** The image also displays "#2(8.3)" and "P-value= ___" indicating a section in a textbook or workbook and a space for calculation entry, respectively.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c6c584e-06c5-4678-ab7c-bac672fd186a%2F527c77d4-e506-437c-a447-e3c862237a45%2Fgw4g2qf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Internet Visits Analysis**
A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits to a particular website per user from home. A random sample of 31 Internet users yielded a sample mean of 38.1 visits with a standard deviation of 5.3. At the 0.02 level of significance, can it be concluded that this differs from the national average? Assume the population is normally distributed. Use a TI-83 Plus/TI-84 Plus calculator for the calculation.
### Hypothesis Test
1. **State the Hypotheses:**
- \( H_0: \mu = 36 \) (not claim)
- \( H_1: \mu \neq 36 \) (claim)
2. **Type of Test:**
- A two-tailed test
3. **P-value:**
- To be calculated
**Note:** The image also displays "#2(8.3)" and "P-value= ___" indicating a section in a textbook or workbook and a space for calculation entry, respectively.
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