Please round 4 dec places , find value .Reject null hypothesis or not?Do you have evidence? **Internet Visits Analysis**A U.S. Web Usage Snapshot indicated a monthly average of 36 Internet visits to a particular website per user from home. A random sample of 31 Internet users yielded a sample mean of 38.1 visits with a standard deviation of 5.3. At the 0.02 level of significance, can it be concluded that this differs from the national average? Assume the population is normally distributed. Use a TI-83 Plus/TI-84 Plus calculator for the calculation.### Hypothesis Test1. **State the Hypotheses:** - $ H_0: \mu = 36 $ (not claim) - $ H_1: \mu \neq 36 $ (claim)2. **Type of Test:** - A two-tailed test3. **P-value:** - To be calculated**Note:** The image also displays "#2(8.3)" and "P-value= ___" indicating a section in a textbook or workbook and a space for calculation entry, respectively.

Answered: Image /qna-images/answer/527c77d4-e506-437c-a447-e3c862237a45.jpg

Answered: Internet Visits A U.S. Web Usage…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the six steps of hypothesis testing to answer the following question. Remember to determine if the problem is a Z test or T test as that will influence your critical value. You believe you have discovered a topical solution that heals wounds faster. The average number of days it takes to remove stiches after surgery in all hospital patients is 12. In a sample of 29 patients the average number of days to remove stiches is 10.5 with a std dev. Of 1.2 Did your solution lessen the number of days patients had stiches
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Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is u= 13.00 Mbps. The sample size is n= 25 and the test statistic is t= - 1.144. P-value = (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check Answer MacBook Pro 888 --- F10 FII F12 esc F3 F7 F9 F4 F5 F6 FB F1 F2 @ #3 2$ & 7 8. 9 Q W E Y tab
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A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Carpeted Uncarpeted 9.4 9.1 16 10.8 6.4 10.8 14.8 8.8 11.5 11.6 13.7 9.4 10.7 12.4 13.4 7.8 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. OA Ho P1 H2 B. Ho H1 F2 OC Ho H= H2
The p-value for a hypothesis test turns out to be 0.0534. At a 3% level of sigrnificance, what is the proper decision? O Reject Ho O Fail to reject Ho Check Answer e Type here to search
explain please
(Use a=.05)
For each scenario below read the given null and alternative hypotheses statements as well as the initial decision about the null hypothesis. Post a conclusion about the claim in each test. (This means when you post your answer, you do not need to include any statement about the null hypothesis. Only the final conclusion is needed.) **Chart 1 is attached** 1 Winning team data were collected for teams in different spots. use a .05 level of significance to test the claim that home/visitor wins are independent of the sport. **Table 1 is attached** P-Value=0.762
Describe type I and type II errors for a hypothesis test of the indicated claim. A furniture store claims that at least 40% of its new customers will return to buy their next piece of furniture. Describe the type I error. Choose the correct answer below. OA. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is at least 0.40, but you fail to reject Ho: p20.40. OB. A type I error will occur when the actual proportion of new customers who return to buy their next piece furniture is at least 0.40, but you reject Ho: p20.40. OC. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is no more than 0.40, but you reject Ho: p ≤ 0.40. OD. A type I error will occur when the actual proportion of new customers who return to buy their next piece f furniture is no more than 0.40, but you fail to reject Ho: p ≤0.40. Describe the type II error. Choose the correct answer…

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