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Internal shear force (V), and internal bending moment (M) at the following locations: qo L3 D B 4 of A e C Mc

Internal shear force (V), and internal bending moment (M) at the following locations: qo L3 D B 4 of A e C Mc

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
- A frame supports both a linear distributed load and a concentrated moment, as shown in the figure below. The distributed load has a magnitude qo = 140 N/m at point B which decreases linearly to zero at point C. The concentrated moment has a magnitude Mc = 79 N - m and acts at point C. The frame is held in equilibrium by a pin at point A and a cable BD. The horizontal and vertical dimensions are given as: L₁ = 7 m, L₂ = 1.5 m , and L3 13 m. Neglect the thickness and weight of the frame for this analysis. Determine the internal normal force (P), internal shear force (V), and internal bending moment (M) at the following locations: qo = L3 D B f A DO e IC Mc
Transcribed Image Text:- A frame supports both a linear distributed load and a concentrated moment, as shown in the figure below. The distributed load has a magnitude qo = 140 N/m at point B which decreases linearly to zero at point C. The concentrated moment has a magnitude Mc = 79 N - m and acts at point C. The frame is held in equilibrium by a pin at point A and a cable BD. The horizontal and vertical dimensions are given as: L₁ = 7 m, L₂ = 1.5 m , and L3 13 m. Neglect the thickness and weight of the frame for this analysis. Determine the internal normal force (P), internal shear force (V), and internal bending moment (M) at the following locations: qo = L3 D B f A DO e IC Mc
y L Pe= V₂ = Me= D → L₁ L₂ Note: Express your answers following the standard sign convention for internal normal force, internal shear force, and internal bending moment as described in the textbook. (a) Point e, which lies 1 m to the left of point C. X number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) (b) Point f, which lies 4 m above point A. P₁ = V₁ = Mƒ= number (rtol-0.01, atol-1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) N N N-m N N ? A N-m ? ?
Transcribed Image Text:y L Pe= V₂ = Me= D → L₁ L₂ Note: Express your answers following the standard sign convention for internal normal force, internal shear force, and internal bending moment as described in the textbook. (a) Point e, which lies 1 m to the left of point C. X number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) (b) Point f, which lies 4 m above point A. P₁ = V₁ = Mƒ= number (rtol-0.01, atol-1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) N N N-m N N ? A N-m ? ?
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