Integrate: [ sin³ 3x cos5 3x dx [sin³ 3x cos³ 3x dx = [ {ITEM D1} dx = [((ITEM D2]) cos5 3x sin 3x dx cos5 3x sin 3x dx - dx - √ cos² 3x sin 3x dx ſ Let u = cos 3x du dx =f cos (ITEM D3} {ITEM D4} = sin 3x dx = =√₁² (du)-[₁² (²) 3 3 ={ITEM D5} = {ITEM D6} + {ITEM D7}+C
Integrate: [ sin³ 3x cos5 3x dx [sin³ 3x cos³ 3x dx = [ {ITEM D1} dx = [((ITEM D2]) cos5 3x sin 3x dx cos5 3x sin 3x dx - dx - √ cos² 3x sin 3x dx ſ Let u = cos 3x du dx =f cos (ITEM D3} {ITEM D4} = sin 3x dx = =√₁² (du)-[₁² (²) 3 3 ={ITEM D5} = {ITEM D6} + {ITEM D7}+C
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Complete the missing ones: (those highlighted ones)
Integrate:
S
sin³ 3x cos5 3x dx
[ sin³ 3x cos³ 3x dx = [ {ITEM D1} dx
= [((ITEM D2]) cos5 3x sin 3x dx
cos5 3x sin 3x dx.
x dx - [ cos²:
cos7 3x sin 3x dx
= cos53
Let u = cos 3x
du
dx
{ITEM D3}
{ITEM D4} = sin 3x dx
=
= [u³ (¯-du) - [ u² (¯-du)
3
3
={ITEM D5}
= {ITEM D6} + {ITEM D7} + C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cdb4c9c-3700-4137-91b7-84cf3024b551%2Fcb13e5a0-807a-48d8-bcef-d5c080bda248%2Fn3a57jv_processed.png&w=3840&q=75)
Transcribed Image Text:Complete the missing ones: (those highlighted ones)
Integrate:
S
sin³ 3x cos5 3x dx
[ sin³ 3x cos³ 3x dx = [ {ITEM D1} dx
= [((ITEM D2]) cos5 3x sin 3x dx
cos5 3x sin 3x dx.
x dx - [ cos²:
cos7 3x sin 3x dx
= cos53
Let u = cos 3x
du
dx
{ITEM D3}
{ITEM D4} = sin 3x dx
=
= [u³ (¯-du) - [ u² (¯-du)
3
3
={ITEM D5}
= {ITEM D6} + {ITEM D7} + C
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