Integral of Vector A= p sin(p)ae +z?cos( q)az along L243L2L1180°L330°100.-6.256.25The closed surface integral of vectorA =Pp cos oa, +22Over the cylinder specified by 0s Z s 2, p = 20.4T16 T32m

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Integral of Vector A= p sin(p)a tz?cos( q)az along L2 L2 L1 180° L3 30° 10 -6.25 6.25 The closed surface integral of vector A =+P cos pa,+ 22 a Over the cylinder specified by 0 sZ s 2, p = 2 0. 4Tt 16 TL 32m 口□

Integral of Vector A= p sin(p)a tz?cos( q)az along L2 L2 L1 180° L3 30° 10 -6.25 6.25 The closed surface integral of vector A =+P cos pa,+ 22 a Over the cylinder specified by 0 sZ s 2, p = 2 0. 4Tt 16 TL 32m 口□

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Integral of Vector A= p sin(p)ae +z?cos( q)az along L2
43
L2
L1
180°
L3
30°
10
0.
-6.25
6.25
The closed surface integral of vector
A =P
p cos oa, +22
Over the cylinder specified by 0s Z s 2, p = 2
0.
4T
16 T
32m

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