(1 Dz î V x B= db y + M.EDE VXB MEDE at colo = 10/0 ə az = (1 M.E. DE Ea at D B O 32B) -4 (0-0) +k (0-0) = 4.E. DE at M•Hm Cos(@t-Bz) = 11.EDE (-p) Hm Sin (@t-B²) = ².2 at

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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How did they do vector calculation explain simply?
Vx B= y + M.Eg
at
VXB = M.E. DE
at
Oz
D B
O
162B) -1 (0-0) + k (0-0) = 4.6.2 E
т(ав
at
ME. DE
at
12 M.Hm Cos (@t-Bz) = μ1.@E
OZ
at
îto (-p) Hm sin (@t-B²) = x.
at
- ↑ BHm Sin(@t-B²)
E.
on integration
Ē= BHmCas(wt-B²) î
+wEo
110
E=_1³__ Hm Ces (@t-p²) 2
os E. PH
orl
@E.
Transcribed Image Text:Vx B= y + M.Eg at VXB = M.E. DE at Oz D B O 162B) -1 (0-0) + k (0-0) = 4.6.2 E т(ав at ME. DE at 12 M.Hm Cos (@t-Bz) = μ1.@E OZ at îto (-p) Hm sin (@t-B²) = x. at - ↑ BHm Sin(@t-B²) E. on integration Ē= BHmCas(wt-B²) î +wEo 110 E=_1³__ Hm Ces (@t-p²) 2 os E. PH orl @E.
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