int sum, k, i, j; int x[4][4]={1,2,3,4},{5,6,7,8},{9,8,7,3},{2,1,7,1}; sum=x[0][0]; for (k=1; k<=3;k++) sum+=x[k] [k]; Give the value in sum after the statements are executed:
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![int sum, k, i, j;
int x[4] [4]={1,2,3,4}, {5,6,7,8},{9,8,7,3},{2, 1,7,1};
sum=x[0] [0];
for (k=1; k<=3;k++)
sum+=x[k] [k];
Give the value in sum after the statements are executed:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F521df3ae-8e5f-4edb-bcc7-9453c7ca96c5%2Ff6094e0d-6a3f-4f15-b6da-130d0145fdde%2Fvngu9q_processed.jpeg&w=3840&q=75)
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- Question 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews Odont give the same solution again .10 min left fast Array Indexing: Knowing the basics of array indexing is important for analysing and manipulating the array object. NumPy offers many ways to do array indexing. O slicing: Just like lists in python, NumPy arrays can be sliced. As arrays can be multidimensional, you need to specify a slice for each dimension of the array. O Integer array indexing: In this method, lists are passed for indexing for each dimension. One to one mapping of corresponding elements is done to construct a new arbitrary array. O Boolean array indexing: This method is used when we want to pick elements from array which satisfy some conditionin C programing Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6, 7, 7, 12, then isSorted(a, 5) should return 1 . If array b stores 3, 4, 9, 8, then isSorted(b,4) should return 0.int isSorted(int *array, int n){
- Assignment Write a program that reads a 2D array of chars, checks, and corrects each char within this array, and print out the corrected 2D array. First the program will read the row count (rowCount) and column count (columnCount) of the 2D array, both as int values. Then, the chars constituting the 2D array will be read on a row-by-row basis. After reading the 2D array, the program will check and correct each char within the 2D array according to the rules below. This process MUST be done by using a void function by sending the appropriate cell of the 2D array with a call-by-reference fashion. • If the row index is an even number, a char can only be a lowercase English value. • If the row index is an odd number, a char can only be ?, 7', or X'. • Any incorrect value MUST be changed into Finally, the checked and corrected 2D array will be printed out to the screen. NOTE: Checking the correctness of a char and correcting it (if necessary) MUST be done in the function with a…Write the function lastOf which searches the array a for the last occurance of any value contained in the array b. Returns the index if found. If not found, return -1. arrays.cpp 1 #include 2 3 int lastof(const int a[), int alen, const int b[], int blen) 4 { int res = 0; for (int i = 0; i =0 ; j--) if (b[j] == a[i]) { if(res[1, 9, 4, 5, 1, 5, 1, 12, 8, 11, 2, 11, 7, 8] b1->[7, 5, 9] last0f(al, 14, b1, 3): -1 Expected: 12 al->[1, 9, 4, 5, 1, 5, 1, 12, 8, 11, 2, 11, 7, 8] b2->[7, 7] lastof (al, 14, b2, 2): -1 Expected: 12 a2->[3, 2, 1, 14, 10, 6, 13, 1ө, 11, 13, 14] b2->[7, 7] lastof (a2, 11, b2, 2): -1 Expected: -1 а2->[3, 2, 1, 14, 10, 6, 13, 1ө, 11, 13, 14] b1->[7, 5, 9] last0f (a2, 11, b1, 3): -1 Expected: -1 а2->[3, 2, 1, 14, 10, 6, 13, 10, 11, 13, 14] b3->[11, 2, 1, 15] lastof (a2, 11, b3, 4): -1 Expected: 8 Score 2/5int X[900]; int Y[600]; int sum, sum1, sum2, sum3; //parallelism : dividing outer loop in three parts //i = 1 to 300 for(i=1;i<=300;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 301 to 600 for(i=301;i<=600;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 601 to 900 for(i=601;i<=900;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } sum = sum1 + sum2 + sum3;} another way to solve the question that send in the pic
- Find error #include<bits/stdc++.h> using namespace std; class Solution{ public: bool isPossible(vector<int>ank,int n,int mid) { int count=0; for(int i=0;i<rank.size()) { int val= (-1 + sqrt(1+(8*mid)/rank[i]))/2; count+=val; } return count>=n; } int findMinTime(int N, vector<int>&A, int L){ int low=*min_element(A.end()),high=1000000; int ans=high; while(low<=high) { int mid=low+(high)/2; if(isPossible(A,mid)) { ans=mid; high=mid; } else low=mid; } return ans; } }; int main() { int t; cin>>t; while(t--) { int l; cin >> l; vector<int>arr(l); for(int i = 0; i < l; i++){ cin >> arr[i]; } Solution ob; int ans = ob.findMin(n, *arr, l); cout…void func(vector<string>& names){ sort(names.begin(), names.end()); //(a) for(int i = names.size() - 1; i > 0; --i){. //(b) if(names[i] == names[i - 1]){ names[i] = move(names.back()); names.pop_back(); } } } What are the reasons or consequences for the programmer’s choice to loop backwards in the line marked (b), and under what circumstances would the algorithm behave differently if that line were replaced with: for (int i = 1; i < names.size(); ++i) ? What would change?#include<bits/stdc++.h> using namespace std; void bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } } int binarySearch(int arr[], int l, int r, int x, int& comp) { comp++; if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] > x) { return binarySearch(arr, l, mid - 1, x, comp); } return binarySearch(arr, mid + 1, r, x, comp); } return -1; } int main() { int Num[8192]; srand(time(NULL)); for (int i = 0; i < 8192; i++) { Num[i] = rand() % 10001; } clock_t starting_time = clock(); bubbleSort(Num, 8192); clock_t ending_time = clock(); clock_t result =…
- main.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];6.Code for- an array of meeting time intervals consisting ofstart and end times [[s1,e1],[s2,e2],...] (si < ei),determine if a person could attend all meetings. For example,Given [[0, 30],[5, 10],[15, 20]],return false.""".- onl Answered: Write a progran Answered: Write a program Answered: The results from 1 Blended Asse as.msu.edu.my msu college Blended Assessment System (B I & sity Part E Question 1 Part E Question 2 Part E Question 3 Part E Question 4 Part E Question 5 Part E Quest Question 3 Two-dimensional arrays can be initialized when they are declared. Given: int integer [4] [3] {{3,2,1}, {4,4,2}, {5,3,0}, {1,0,4}}; Write the for loop to: (a) Find the total of row 2 of the array. (b) Find the total of column 1 of the array. (c) Find the total of each individual row. (d) Find the total of each individual column. (e) Initialize column 2 to 0. [25 Mark] Please write your answer below: Source ABC BIUS x, Styles Format Font Size A-A hp liti
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