int number, sum=0; int counter; for (counter= 0; counter< 4; counter++) { sum= sum + number;
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- Convert the C function below to MIPS assembly language. Make sure you follow the MIPS calling conventions. unsigned int sum(unsigned int n) { if (n == 0) return %; else return n+ sum(n-1); %3D%3D13. Given the following Java loop, write the equivalent MIPS instructions. for (int i = 5; i < 75; i =i+ 10) { for (int j = 3; j< 40; j=j+ 13) { }Convert the following from Python to RISC-V Assembly Language:
- In the recursive factorial code given below, what happens if the instruction at line number 0x00400040 (addi $sp,$sp,8) is deleted by mistake from the following code? Ox00400028 fact: addi 0x0040002C 0x00400030 0x00400034 0x00400038 0x0040003C 0x00400040 0x00400044 0x00400048 L1: 0x0040004C 0x00400050 0x00400054 0x00400058 0x0040005C 0x00400060 SW SW siti beq addi ANSWER. addi jr addi jal Iw Iw $sp,$sp, -8 $ra, 4($sp) $a0, 0($sp) $t0, $a0, 1 $t0, $zero, L1 $v0, $zero, 1 $sp,$sp, 8 $ra $a0, $a0, -1 fact $a0, 0($sp) $ra, 4($sp) addi $sp,$sp,8 mult $v0, $a0,$v0 jr $ra Possible answers are as follows: a) Program enters an infinite loop and remains in the loop with the correct value stored in the vo register b) Program enters an infinite loop and remains in the loop with incorrect return value in the vo register c) Program enters an infinite loop and crashes due to memory access that exceeds the stack space d) Program will terminate properly but produce an incorrect return value in vo…Programming Project: For Loops Write an Assembly Language Program that produces the Times Table for a specific integer value between 1 to 12. NOTE: You choose and hard code only one value (i.e. 7) and produce the times table for that value. Also note that since you are using registers and memory locations make sure that at each step you screen shot each result for each part of the Times Table. For example 7 x 12 = 84 but in Hexadecimal the value is 54. Sample code in C #include void main() ( int i, j; printf("Enter an integer: "); scanf("%d", &i); printf("Times %d Table\n", i). for(j = 0; j<= 12; j =j+1) { printf("%d x %d = %d\n", j, 1. j'i); } printf("\n");Perform multiplication using x86 Assembly Language Program that user needs to input two numbers and multiply it on the result. Sample Output: Enter First Number: 3 Enter Second Number: 3 Result: 9
- Assembly language use masmAssignment for Computer Architecture The assignment is to create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. The program’s output should look something like the following where the xxx’s are the numbers you chose. The resulting numbers may be different than mine depending on your choice of a, b, and c. Using a = xxx, b = xxx, and c = xxx a + (b + c) = 0 (a + b) + c = 1 The key is to have two of the number large (one positively and one negatively but equal in magnitude) floating point numbers and the third floating point number very small in comparison. As a side note, the associative law will also fail for multiplication for floating point numbers, but you do not need to demonstrate that. Please don't forget to include comments in this codeImplement the following pseudocode in assembly language. Use short-circuit evaluationand assume that X is a 32-bit variable.if( ebx > ecx ) OR ( ebx > val1 )X = 1elseX = 2
- Can someone help me draw a flow-diagram of this code in LC3 assembly language. Would appreciate it. .ORIG x3000 isPrime ST R1, SAVE_R1 ; Save the original value of R1 AND R1, R1, #0 ; Clear R1 (to use as a counter) BRz ZERO_CASE ; Handle the case when the input is 0 LOOP ADD R1, R1, #1 ; Increment the counter ADD R1, R1, #1 ; Check for divisibility by counter + counter DIV R0, R1 ; Divide the input by (counter + counter) BRnp IS_PRIME ; If the remainder is not 0, the number is prime BRz NOT_PRIME ; If the remainder is 0, the number is not prime IS_PRIME AND R0, R0, #0 ; Clear R0 ADD R0, R0, #1 ; Set R0 to 1 (prime) BRnzp DONE ; Branch to DONE NOT_PRIME AND R0, R0, #0 ; Clear R0 (not prime) BRnzp DONE ; Branch to DONE ZERO_CASE AND R0, R0, #0 ; Clear R0 (0 is not prime) DONE LD R1, SAVE_R1 ; Restore the original value of R1 RET ; Return from the function SAVE_R1 .BLKW 1 ; Storage for saving…Is the assembly language version of a FOR loop, WHILE loop, DO WHILE loop, GOTO loop function the same or different? If different,identify the differences. Your comparison should be based on: Number of registers used Number of jumps (iterations) Total number of operationsWrite the machine code of the instruction: subwf Ox53, 1 How to write answer: Write 4-digits hexadecimal value starting without '0x'. Example: if answer is 0X245F, then write 245F Example: if answer is 0X005F, then write 005F Answer: