int fib (int n) { if (n==0) return 0; else if (n (n == 1) return 1; else return fib (n-1) + fib (n-2);
int fib (int n) { if (n==0) return 0; else if (n (n == 1) return 1; else return fib (n-1) + fib (n-2);
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Implement the following C code in RISC-V assembly. Hint: Remember that the stack pointer must remain aligned on a multiple of 16.

Transcribed Image Text:```c
int fib(int n) {
if (n == 0)
return 0;
else if (n == 1)
return 1;
else
return fib(n-1) + fib(n-2);
}
```
### Description
This code is a recursive implementation of a function in C that calculates the Fibonacci number for a given integer \( n \).
#### Explanation:
- **Function Definition**: `int fib(int n)` declares a function named `fib`, which takes an integer `n` as input and returns an integer.
- **Base Cases**:
- If `n` is 0, the function returns 0.
- If `n` is 1, the function returns 1.
- **Recursive Case**:
- For all other values of `n`, the function returns the sum of the Fibonacci numbers of the two preceding numbers: `fib(n-1)` and `fib(n-2)`.
This implementation follows the mathematical definition of the Fibonacci sequence, where each number is the sum of the two preceding ones, usually starting with 0 and 1. The function uses recursion to break down the problem into smaller subproblems.
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