Instructions: Answer the following question based upon your observations in Table 1. (refer to the photo below for the table) How does the direction of motion of electrons change, when polarity of plates changes? What happens to the motion of electrons when potential is constant? What do you think are reasons? Answer:
Instructions: Answer the following question based upon your observations in Table 1. (refer to the photo below for the table) How does the direction of motion of electrons change, when polarity of plates changes? What happens to the motion of electrons when potential is constant? What do you think are reasons? Answer:
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Instructions: Answer the following question based upon your observations in Table 1. (refer to the photo below for the table)
How does the direction of motion of electrons change, when polarity of plates changes? What happens to the motion of electrons when potential is constant? What do you think are reasons?
Answer: ______________________________________________________________________________________________________________________________________________________________________________________
![Quantity
Observations
Reasons
Charge (Q on caраcitor
Increasing potential charge on
capacitor will increase
9 = ev
Area A, and separation d is
Capacitance =
constant. Therefore, capacitance (C)
is also constant.
Capacitance (C) of capacitor
c =
= constant
on
increasing the potential
The increasing potential of battery
potential across capacitors will also
Potential (V) across capacitor
C = v
increase.
This happens because,
Potential difference = Electric field
* distance
Slowly increasing potential would
result in steady increase in electric
field between the parallel plates.
Electric Field (E) between plates
As the value of distance between
the plates is kept constant so
Electric field is directly
proportional to potential ie
Ec V
According to equation (1), Electric
field is directly proportional to
Applied potential difference and
inversely proportional to distance
between plates. distance remains
constant, so electric field is directly
proportional to Applied potential
difference. When potential increases
slowly, so potential difference also
increases, it means the electric field
between plates also increases.
Direction of motion of electrons
the electric field between plates
through battery
increases](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e977142-b7ea-4429-b36a-3c3d76a7b334%2Fa311bd54-9095-4bda-ae46-aa5fe020a705%2Fsq1m7fb_processed.png&w=3840&q=75)
Transcribed Image Text:Quantity
Observations
Reasons
Charge (Q on caраcitor
Increasing potential charge on
capacitor will increase
9 = ev
Area A, and separation d is
Capacitance =
constant. Therefore, capacitance (C)
is also constant.
Capacitance (C) of capacitor
c =
= constant
on
increasing the potential
The increasing potential of battery
potential across capacitors will also
Potential (V) across capacitor
C = v
increase.
This happens because,
Potential difference = Electric field
* distance
Slowly increasing potential would
result in steady increase in electric
field between the parallel plates.
Electric Field (E) between plates
As the value of distance between
the plates is kept constant so
Electric field is directly
proportional to potential ie
Ec V
According to equation (1), Electric
field is directly proportional to
Applied potential difference and
inversely proportional to distance
between plates. distance remains
constant, so electric field is directly
proportional to Applied potential
difference. When potential increases
slowly, so potential difference also
increases, it means the electric field
between plates also increases.
Direction of motion of electrons
the electric field between plates
through battery
increases
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