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Instructions : Write the answer in the paper only. Do not write any answer in the box. PROBLEM [ B4]: Two resistors R1 and R2 are connected in parallel in an electric circuit. If the resistance R1 is changed from 10 to 10.2 ohms and R2 is changed from 26 to 25.8 ohms, find the absolute change, relative change and percentage change in the total resistance R.

Instructions : Write the answer in the paper only. Do not write any answer in the box. PROBLEM [ B4]: Two resistors R1 and R2 are connected in parallel in an electric circuit. If the resistance R1 is changed from 10 to 10.2 ohms and R2 is changed from 26 to 25.8 ohms, find the absolute change, relative change and percentage change in the total resistance R.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Instructions : Write the answer in the paper only. Do not write any answer in the box. PROBLEM [ B4 ] : Two resistors R1 and R2 are connected in parallel in an electric circuit. If the resistance Rị is changed from 10 to 10.2 ohms and R2 is changed from 26 to 25.8 ohms, find the absolute change, relative change and percentage change in the total resistance R.
Transcribed Image Text:Instructions : Write the answer in the paper only. Do not write any answer in the box. PROBLEM [ B4 ] : Two resistors R1 and R2 are connected in parallel in an electric circuit. If the resistance Rị is changed from 10 to 10.2 ohms and R2 is changed from 26 to 25.8 ohms, find the absolute change, relative change and percentage change in the total resistance R.
Expert Solution
Step 1

Given:

R1=10 Ω

R'1=10.2 Ω

R2=26 Ω

R'2=25.8 Ω

Step 2

For initial equivalent resistance in parallel circuit:

Req=R1R2R1+R2⇒Req=10×2610+26=26036=7.2 Ω

For changed equivalent resistance in parallel circuit:

R'eq=R'1R'2R'1+R'2=10.2×25.810.2+25.8=263.1636⇒R'eq=7.31 Ω

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