Instructions: Assume that the distribution for the following scenario is normal. Use the standard normal table to find the probability. Round z-scores to the nearest hundredth. Do not round the probability from the table. The average daily jail population in the United States is 618,319. If the distribution is normal and the standard deviation is 50,200, find the probability that on a randomly selected day, the jail population is: Between 500,000 and 600,000 P(500, 000 < x < 600, 000) = P( < z <

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Instructions: Assume that the distribution for the following scenario is normal. Use the
standard normal table to find the probability. Round z-scores to the nearest hundredth. Do
not round the probability from the table.
The average daily jail population in the United States is 618,319. If the distribution is normal
and the standard deviation is 50,200, find the probability that on a randomly selected day,
the jail population is:
Between 500,000 and 600,000 P(500, 000 < x < 600, 000) = P(
< z <
)=
Transcribed Image Text:Instructions: Assume that the distribution for the following scenario is normal. Use the standard normal table to find the probability. Round z-scores to the nearest hundredth. Do not round the probability from the table. The average daily jail population in the United States is 618,319. If the distribution is normal and the standard deviation is 50,200, find the probability that on a randomly selected day, the jail population is: Between 500,000 and 600,000 P(500, 000 < x < 600, 000) = P( < z < )=
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