Instruction: Answer the following systematically. Strictly follow the format of the solution (Example problem + complete solution is provided in the photos below). I WON'T LIKE YOUR ANSWER IF IT IS NOT PROPERLY FOLLOWED AND INCORRECT) A small furniture shop makes tables and chairs which must be processed through assembly and finishing processes. The assembly department is available for 60 hours in every production period while the finishing department is available for 48 hours of work. Making one table requires 4 hours to assemble and 2 hours to finish. Each chair requires 2 hours to assemble and 4 hours to finish. One table contributes P500 to the profit, while a chair contributes P300. Determine the number of tables and chairs to make per production period to maximize profit, assuming all tables and chairs are sold.    Objectives: Maximize

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Instruction: Answer the following systematically. Strictly follow the format of the solution (Example problem + complete solution is provided in the photos below). I WON'T LIKE YOUR ANSWER IF IT IS NOT PROPERLY FOLLOWED AND INCORRECT)

A small furniture shop makes tables and chairs which must be processed through assembly and finishing processes. The assembly department is available for 60 hours in every production period while the finishing department is available for 48 hours of work. Making one table requires 4 hours to assemble and 2 hours to finish. Each chair requires 2 hours to assemble and 4 hours to finish. One table contributes P500 to the profit, while a chair contributes P300. Determine the number of tables and chairs to make per production period to maximize profit, assuming all tables and chairs are sold. 

 

Objectives: Maximize

 

EXAMPLE PROBLEM + SOLUTION
(PLEASE FOLLOW THE FORMAT OF HOW TO SOLVE PROPERLY)
A powerplant burns coal, oil, and gas to general electricity. Suppose each ton of coal costs, P200,000
generates 600 kilowatts and emits 20 units of sulfur dioxide and 15 units of a particular matter. Each ton
of oil costs P220,000 generates 550 kilowatts and emits 18 units of sulfur dioxide and 12 units of a
particular matter. Each ton of gas costs P250,000 generates 500 kilowatts and emits 15 units of sulfur
dioxide and 10 units of a particulate matter. The Department of Environment and Natural Resources
restricts the daily emission of sulfur dioxide to not more than 60 units and not more than 75 units of
particulate matter. If the powerplant wants to spend not more than P1,200,000 per day on fuel, how much
of each type should be used to maximize the amount of power generated?
Maximize:
PG = 600x, + 550x, + 500x,
20x, + 22x, + 25x, s 120
20x, + 18x, + 15x, s 60
15x, + 12x, + 10x, s 75
Subject to:
Maximize:
PG = 600x, + 550x, + 500x, + 0S, + 0s, + os,
20x, + 22x, + 25x, + S, = 120
20x, + 18x, + 15x, + S, = 60
15x, + 12x, + 10x, + S,
Subject to:
+ S. =
75
*, S, 2 0
Table 1.
600
550
500
Var
Qty
120
20
22
25
60
20
18
15
75
15
12
10
z,
C, – z,
600
50
500
Table 2.
600
550
500
Transcribed Image Text:EXAMPLE PROBLEM + SOLUTION (PLEASE FOLLOW THE FORMAT OF HOW TO SOLVE PROPERLY) A powerplant burns coal, oil, and gas to general electricity. Suppose each ton of coal costs, P200,000 generates 600 kilowatts and emits 20 units of sulfur dioxide and 15 units of a particular matter. Each ton of oil costs P220,000 generates 550 kilowatts and emits 18 units of sulfur dioxide and 12 units of a particular matter. Each ton of gas costs P250,000 generates 500 kilowatts and emits 15 units of sulfur dioxide and 10 units of a particulate matter. The Department of Environment and Natural Resources restricts the daily emission of sulfur dioxide to not more than 60 units and not more than 75 units of particulate matter. If the powerplant wants to spend not more than P1,200,000 per day on fuel, how much of each type should be used to maximize the amount of power generated? Maximize: PG = 600x, + 550x, + 500x, 20x, + 22x, + 25x, s 120 20x, + 18x, + 15x, s 60 15x, + 12x, + 10x, s 75 Subject to: Maximize: PG = 600x, + 550x, + 500x, + 0S, + 0s, + os, 20x, + 22x, + 25x, + S, = 120 20x, + 18x, + 15x, + S, = 60 15x, + 12x, + 10x, + S, Subject to: + S. = 75 *, S, 2 0 Table 1. 600 550 500 Var Qty 120 20 22 25 60 20 18 15 75 15 12 10 z, C, – z, 600 50 500 Table 2. 600 550 500
Var
Qty
's
60
4.
10
-1
600
3
9/10
3/4
1/20
30
-3/2
-5/4
-3/4
z,
1800
540
30
600
450
C, - Z,
10
50
-30
Table 3.
600
550
500
Var
Qty
20
-40/3
-8
-5/3
500
X,
4
4/3
6/5
1/15
s,
5/3
-2/3
35
z,
2000
2000/3
600
500
100/3
C, - Z,
-200/3
-50
-100
Decision:
Coal = 0,
%3D
Oil = 0,
Gas = 4,
Maximum Power Generated of 2, 000 kilowatts.
Transcribed Image Text:Var Qty 's 60 4. 10 -1 600 3 9/10 3/4 1/20 30 -3/2 -5/4 -3/4 z, 1800 540 30 600 450 C, - Z, 10 50 -30 Table 3. 600 550 500 Var Qty 20 -40/3 -8 -5/3 500 X, 4 4/3 6/5 1/15 s, 5/3 -2/3 35 z, 2000 2000/3 600 500 100/3 C, - Z, -200/3 -50 -100 Decision: Coal = 0, %3D Oil = 0, Gas = 4, Maximum Power Generated of 2, 000 kilowatts.
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