Instruction:(a) Based on the information provided, determine the structures of compounds.(b) Assign all peaks in ¹H and ¹³C NMR spectra of compoundsCompound 4:4000IR Spectrum(liquid film)100k8060of base peak% of10403000Lind13C NMR Spectrum(50.0 MHz, CDCI, solution)DEPTproton decoupled9200¹H NMR Spectrum(200 MHz, CDCI, solution)9180 120 160m/e82000v (cm¹)16071600expansion3.0M**198/20062001200120800Mass Spectrum2.5Resolves intotwo signals at higher fieldCgH₁1 Br240 280Resolves intotwo signals at higher field10solvent80ppm0.00.51.01.53absorbance20040UV spectrum5.30mg/10mispath length: 1.00 cmsolvent: cyclohexane2502expansions2 (nm)30035.0 34.001ppm3508 (ppm)TMS08 (ppm)

The chemical formula of an organic compound provides information about the presence of the specific…

Instruction: (a) Based on the information provided, determine the structures of compounds. (b) Assign all peaks in ¹H and C NMR spectra of compounds Compound 4: IR Spectrum (quid ) 4000 88888 dadadadadadadadadad % of base peak www 40 10 3000 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT 80 proton decoupled 9 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 8 ww 2000 120 v (cm¹) m/e 160 160 7 1600 expansion 3.0 M 198/200 6 1200 200 240 120 Mass Spectrum 800 Resolves into two signals at higher field 2.5 C₂H₁1Br 280 Resolves into two signals at higher eld 5 solvent 80 ppm 0.0 1.0 3 wwwwwww absorbance 200 40 UV spectrum 5.30 mg/10 mis path length: 1.00 cm solvent: cyclohexane 250 2 expansions 2 (nm) 300 35.0 34.0 0 1 ppm 350 8 (ppm) TMS 0 8 (ppm)

Instruction: (a) Based on the information provided, determine the structures of compounds. (b) Assign all peaks in ¹H and C NMR spectra of compounds Compound 4: IR Spectrum (quid ) 4000 88888 dadadadadadadadadad % of base peak www 40 10 3000 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT 80 proton decoupled 9 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 8 ww 2000 120 v (cm¹) m/e 160 160 7 1600 expansion 3.0 M 198/200 6 1200 200 240 120 Mass Spectrum 800 Resolves into two signals at higher field 2.5 C₂H₁1Br 280 Resolves into two signals at higher eld 5 solvent 80 ppm 0.0 1.0 3 wwwwwww absorbance 200 40 UV spectrum 5.30 mg/10 mis path length: 1.00 cm solvent: cyclohexane 250 2 expansions 2 (nm) 300 35.0 34.0 0 1 ppm 350 8 (ppm) TMS 0 8 (ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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