Input This program will create a date in the Microsoft Disk Operating System File Allocation Table (DOS FAT) date format. You should write a sequence of instructions which receives three variables in registers as input: M - a month between 1 and 12 (in register 1) D - a day between 1 and 31 (in register 2) Y - a four-digit year value between 1980 and 2127 inclusive (in register 3)   Processing: You must start by validating that these values are all within the appropriate ranges (1-12, 1-31, 1980-2127). If not, place a value of minus one in register 0 and end the program. Then use shift and bitwise instructions to create a Microsoft DOS FAT file system date. This has the format: Year in bits 15..09 Month in bits 08..05 Day in bits 04..00     This is a 16-bit number. The upper bits (31..16) should be set to zero. Output: Output shall be placed in register zero. If any of the parameters are invalid, place a value of minus one in register 0. Grading:   Correct output values for selected test data: 20 points Clean assembly, no error messages: 5 points Validation of input and rejection of incorrect values: 10 points Correct program heading, naming, et cetera: 5 points   Sample Output: For input of R1 = 12, R2 = 4, R3 = 2023, the output in register zero should be hexadecimal 0x568C. Here is how that answer was developed: Year: 2023 - 1980 = 43 43 - seven bits: 0101011 Month: 4 - four bits: 0100 Day: 12 - five bits: 01100 Putting it all together: 0101011 0100 01100 0101011010001100 0101 0110 1000 1100 5 6 8 C   For input of R1 = 1, R2 = 1, R3 = 1980, the output in register zero should be hexadecimal 0x0021. For input of R1 = 13, R2 = 13, R3 = 2013, the output in register zero should be minus one. 2023 - 1980 = 43 = 29 = 0b0101001; 4 = 0b0100; 12 = 0b01100; 0b0101001010001100; 0101 0010 1000 1100 = 0x528C 1980 - 1980 = 0 = 0b0000000; 1 = 0b0001; 1 = 0b00001; 0000000000100001 = 0000 0000 0010 0001 = 0x0021

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Input

This program will create a date in the Microsoft Disk Operating System File Allocation Table (DOS FAT) date format. You should write a sequence of instructions which receives three variables in registers as input:

M - a month between 1 and 12 (in register 1)

D - a day between 1 and 31 (in register 2)

Y - a four-digit year value between 1980 and 2127 inclusive (in register 3)

 

Processing:

You must start by validating that these values are all within the appropriate ranges (1-12, 1-31, 1980-2127). If not, place a value of minus one in register 0 and end the program.

Then use shift and bitwise instructions to create a Microsoft DOS FAT file system date. This has the format:

Year in bits 15..09

Month in bits 08..05

Day in bits 04..00

 

 

This is a 16-bit number. The upper bits (31..16) should be set to zero.

Output:

Output shall be placed in register zero. If any of the parameters are invalid, place a value of minus one in register 0.

Grading:

 

Correct output values for selected test data: 20 points

Clean assembly, no error messages: 5 points

Validation of input and rejection of incorrect values: 10 points

Correct program heading, naming, et cetera: 5 points

 

Sample Output:

For input of R1 = 12, R2 = 4, R3 = 2023, the output in register zero should be hexadecimal 0x568C.

Here is how that answer was developed:

Year: 2023 - 1980 = 43 43 - seven bits: 0101011 Month: 4 - four bits: 0100 Day: 12 - five bits: 01100 Putting it all together: 0101011 0100 01100 0101011010001100 0101 0110 1000 1100 5 6 8 C

 

For input of R1 = 1, R2 = 1, R3 = 1980, the output in register zero should be hexadecimal 0x0021.

For input of R1 = 13, R2 = 13, R3 = 2013, the output in register zero should be minus one.

2023 - 1980 = 43 = 29 = 0b0101001; 4 = 0b0100; 12 = 0b01100; 0b0101001010001100; 0101 0010 1000 1100 = 0x528C
1980 - 1980 = 0 = 0b0000000; 1 = 0b0001; 1 = 0b00001; 0000000000100001 = 0000 0000 0010 0001 = 0x0021

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